以下是我正在嘗試做的簡化版本?；旧衔矣?2 個注冊表，每個表單的內容將寫入不同的表。當我加載表單時，我在第 xx 行收到許多未定義索引錯誤，并且我仍然在第 75 行和第 84 行的這個示例中收到錯誤，我認為錯誤歸因于某些字段是“必需的”，但該頁面尚未加載為它使用一些 JS 飄走了。... 請幫忙！<?phpob_start(); //Turns on output bufferingsession_start(); //This starts a session variable where it store the input so the user doesnt have to start over if they get an error$con = mysqli_connect("localhost","root","","test-sql"); //connection variables $timezone = date_default_timezone_set("Europe/London"); if(mysqli_connect_errno()){ echo "failed to connect:" . mysqli_connect_errno(); }?><html> <head> <! here we add the links and the jquery> <title>Register Project</title> </head> <body> <div id="first"> <form action="test-sql.php" method="POST"> <input type="text" name="Inf_fname" placeholder="First Name" required> <br> <input type="text" name="Inf_lname" placeholder="Last Name" required> </form> </div> <div id="second"> <form action="test-sql.php" method="POST"> <br> <input type="text" name="Cust_fname" placeholder="First Name" required> <br> <input type="text" name="Cust_lname" placeholder="Last Name" required> <br> <input type="submit" name="register_button" value="Register"> </form> </div> </body> </html>
將數據插入 2 個單獨的 mySQL 表
明月笑刀無情
2022-12-29 16:20:43
