烙印99
2022-12-29 16:14:54
我從 API 獲得了很多數組,但 id 的計數不同,我需要檢查匹配[id = region...]并只獲得這個對象。我如何使用正則表達式和來做到這一點find?(5) [{…}, {…}, {…}, {…}, {…}]0: {id: "address.7576869587107444", type: "Feature", place_type: Array(1), relevance: 1, properties: {…}, …}1: {id: "postcode.12959148828066430", type: "Feature", place_type: Array(1), relevance: 1, properties: {…}, …}2: {id: "place.14392640799224870", type: "Feature", place_type: Array(1), relevance: 1, properties: {…}, …}3: {id: "region.9375820343691660", type: "Feature", place_type: Array(1), relevance: 1, properties: {…}, …}4: {id: "country.13200156005766020", type: "Feature", place_type: Array(1), relevance: 1, properties: {…}, …}length: 5__proto__: Array(0).then(res => { let region = /region/gi console.log(res.data.features.find(place => place.id == region.test(place))) setAdrress(res.data) })
2 回答

江戶川亂折騰
TA貢獻1851條經驗 獲得超5個贊
使用String#match
。
console.log(res.data.features.find(place => place.id.match(region)))
const arr = [{id: "address.7576869587107444", type: "Feature"},
{id: "postcode.12959148828066430", type: "Feature"},
{id: "place.14392640799224870", type: "Feature"},
{id: "region.9375820343691660", type: "Feature"},
{id: "country.13200156005766020", type: "Feature"}];
let region = /region/gi;
console.log(arr.find(place => place.id.match(region)))

慕哥9229398
TA貢獻1877條經驗 獲得超6個贊
您可以過濾數組并使用正則表達式檢查以實現該目的。
var regex = RegExp(/^region/); var filtered_arr = arr.filter(obj => regex.test(obj.id));
filtered_arr
將包含您的 id 開頭的對象數組region
使用正則表達式將確保過濾所有以開頭的字符串。region
使用 match 之類的東西會找到region
字符串中任何位置的 id。由于我沒有足夠的聲譽,我無法對第一篇文章發表評論。:)
添加回答
舉報
0/150
提交
取消