我（作為一個絕對的初學者）正在嘗試創建一個簡單的工具，它可以創建一些對象并將它們鏈接起來。這些對象是：客戶許可證（2 種類型，擴展類）這個想法是在創建許可證時使用（其中一個）客戶公司名稱，因此許可證鏈接到客戶。我使用 ArrayLists 來存儲數據。我嘗試使用 Customer cCompany 的 getter，但是當我嘗試實際創建一個新的許可證對象時，我收到有關不兼容類型的錯誤（String to object of type customer）我該如何修復該錯誤？非常感謝任何幫助，但請解釋清楚，我是一個絕對的初學者。我可能把事情復雜化了……部分代碼摘錄：從主要：public class Main { public static void main(String[] args) { //Create customers List <Customer> customers = new ArrayList <> (10); customers.add(new Customer("TestCompany","John Doe",1234567890,"[email protected]"));....//Create Elvis licenses (based on superclass License)List <ElvisLicense> ellicenses = new ArrayList <> (10);ellicenses.add(new ElvisLicense("TestCompany","VendorA",1234,"1234-A","Solutions Server gold","1234-dtbk-87654-nlof",10, true , true));類別： 客戶：class Customer { String cCompany; private String cName; private int cPhone; private String cEmail; public Customer( String cCompany, String cName,int cPhone, String cEmail) { this.cCompany = cCompany; this.cName = cName; this.cPhone = cPhone; this.cEmail = cEmail; } //This getter should be used to link the license to the customer (Done in License.java) public String getcCompany() { return cCompany; }類許可證（超類）class License {// Used no modifier to set access for Class/Package and Subclass inside the packageCustomer licenseCompany;String lVendor;int lContractNumber;String lCertificateNumber;String lProductName;String lLicenseKey;int lNumberOfSeats; public License(Customer cCompany, String lVendor, int lContractNumber, String lCertificateNumber, String lProductName, String lLicenseKey, int lNumberOfSeats) { licenseCompany = cCompany; this.lVendor = lVendor; this.lVendor = lVendor; this.lContractNumber = lContractNumber; this.lCertificateNumber = lCertificateNumber; this.lProductName = lProductName; this.lLicenseKey = lLicenseKey; this.lNumberOfSeats = lNumberOfSeats; }
2 回答
FFIVE
TA貢獻1797條經驗 獲得超6個贊
下面一行是錯誤的。
ellicenses.add(new ElvisLicense("TestCompany","VendorA",1234,"1234-A","Solutions Server gold","1234-dtbk-87654-nlof",10, true , true));
由于許可證需要客戶反對一個參數。相反，您應該首先創建客戶對象。
ellicenses.add(new ElvisLicense(new Customer("TestCompany","VendorA",1234,"1234-A"),"Solutions Server gold","1234-dtbk-87654-nlof",10, true , true));
重復使用它customer list以避免創建公司。
for(Customer customer : customers){
// here you need some way to offer other parameters except customer parameter.
License license = new new ElvisLicense(customer,"Solutions Server gold","1234-dtbk-87654-nlof",10, true , true);
ellicenses.add(license);
}
慕田峪9158850
TA貢獻1794條經驗 獲得超7個贊
您需要做的是在創建對象時使用您已經創建的 Customer 對象之一ElvisLicense。為了更容易地按姓名找到該客戶，我建議您將它們存儲在地圖中，而不是將名稱作為鍵的列表。
Map<String, Customer> customerMap = new HashMap<>();
Customer customer = new Customer("TestCompany","John Doe",1234567890,"[email protected]"));
customerMap.put(customer.getcCompany(), customer);
所以在創建許可證時你要查找客戶
List <ElvisLicense> ellicenses = new ArrayList <> (10);
Customer customer = customerMap.get("TestCompany");
if (customer != null) {
ElvisLicense license = new ElvisLicense(customer,"VendorA",1234,"1234-A","Solutions Server gold","1234-dtbk-87654-nlof",10, true , true));
ellicenses.add(license);
} else {
//If the customer isn't found you need some kind of error handling, better than below :)
System.out.println("Can't create a license, no customer found");
}
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