所以我需要存儲來自系統的輸入，并在通過輸入給出的命令與條件匹配時觸發代碼塊。給定的命令是由系統隨機產生的，每次執行代碼時都不相同。我在下面做的是；我將輸入存儲在一個列表中，直到輸入變成空格，這表明命令已經結束，并且在聲明中特別說明命令將在最后一個命令之后以空格結束。從該命令列表中讀取命令、輸入和值，直到沒有要執行的命令為止。我知道這是不好的做法。由于我是這種語言的新手，我需要一些建議來更改我的代碼。提前致謝。順便說一句，我無法更改 if 語句中的條件，因為通過輸入給定的命令不一樣，但像這樣以及更多：追加 15插入它 0 25remove_it 30代碼工作得很好我需要建議，使它成為良好的代碼實踐，以提高我在 Python 中的水平。i = 0command_list = []while True: command = input('') if command == '': break command_list.append(command) i += 1b = 0arr = []while i != b: command1 = command_list[b] b += 1 if command1[0:8] == "append_it": value = int(command1[9:]) arr.append(value) elif command1[0:4] == "insert_it": index = int(command1[5:7]) value = int(command1[7:]) arr.insert(index, value) elif command1[0:3] == "remove_it": value = int(command1[4:]) if value in liste: arr.remove(value) elif command1[0:] == "print_it": print(arr) elif command1[0:] == "reverse_it": arr.reverse() elif command1[0:] == "sort_it": arr.sort() elif command1[0:] == "pop_it": arr.pop()
1 回答
絕地無雙
TA貢獻1946條經驗 獲得超4個贊
您可以通過在字典中定義要執行的操作、將輸入的值添加為拆分列表并為適當的輸入調用適當的函數來改進：
def appendit(a, *prms):
v = int(prms[0])
a.append(v)
def insertit(a, *prms):
i = int(prms[0])
v = int(prms[1])
a.insert(i,v)
def removeit(a, *prms):
v = int(prms[0])
a.remove(v) # no need to test
def reverseit(a): a.reverse()
def sortit(a): a.sort()
def popit(a): a.pop()
# define what command to run for what input
cmds = {"append_it" : appendit,
"insert_it" : insertit,
"remove_it" : removeit,
"print_it" : print, # does not need any special function
"reverse_it": reverseit,
"sort_it" : sortit,
"pop_it" : popit}
command_list = []
while True:
command = input('')
if command == '':
break
c = command.split() # split the command already
# only allow commands you know into your list - they still might have the
# wrong amount of params given - you should check that in the functions
if c[0] in cmds:
command_list.append(c)
arr = []
for (command, *prms) in command_list:
# call the correct function with/without params
if prms:
cmds[command](arr, *prms)
else:
cmds[command](arr)
輸出：
# inputs from user:
append_it 42
append_it 32
append_it 52
append_it 62
append_it 82
append_it 12
append_it 22
append_it 33
append_it 12
print_it # 1st printout
sort_it
print_it # 2nd printout sorted
reverse_it
print_it # 3rd printout reversed sorted
pop_it
print_it # one elem popped
insert_it 4 99
remove_it 42
print_it # 99 inserted and 42 removed
# print_it - outputs
[42, 32, 52, 62, 82, 12, 22, 33, 12]
[12, 12, 22, 32, 33, 42, 52, 62, 82]
[82, 62, 52, 42, 33, 32, 22, 12, 12]
[82, 62, 52, 42, 33, 32, 22, 12]
[82, 62, 52, 99, 33, 32, 22, 12]
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