您應該將可選匹配項移動到一個捕獲組中：import pandas as pddata = """\2930 Beverly Glen Circle Los Angeles435 S. La Cienega Blvd. Los Angeles12224 Ventura Blvd. Studio City9570 Wilshire Blvd. Beverly Hills26025 Pacific Coast Hwy. Malibu""".split('\n')df = pd.DataFrame(data)print(df)cities = ['Los Angeles', 'Studio City', 'Beverly Hills','Malibu']c = '|'.join(cities)pat = fr'(.*?)\s({c})' # fixed pattern with f and rdf = df[0].str.extract(pat,expand=True)print(df)輸出： 0 10 2930 Beverly Glen Circle Los Angeles1 435 S. La Cienega Blvd. Los Angeles2 12224 Ventura Blvd. Studio City3 9570 Wilshire Blvd. Beverly Hills4 26025 Pacific Coast Hwy. Malibu分享編輯跟隨于 2020 年 6 月 4 日 1
1 回答
婷婷同學_
TA貢獻1844條經驗 獲得超8個贊
這是固定版本。我建議你再做一些工作:)
from random import choice
t = ["rock", "paper", "scissors"]
tie = 0
lose = 0
win = 0
for i in range(0, 10):
print("1... 2... 3... go!")
# you need to refresh these variables on every for iteration
computer = choice(t)
player = None
# if you're using while to make sure player inputs, that's the only thing that needs
# to be within the while loop
while not player:
player = input("rock, paper, scissors: ")
print("Computer: ", computer)
print("User: ", player)
# I would look for a way to simplify determining the winner
if player == computer:
# tie += 1 is the same as tie = tie + 1
tie +=1
print("Tie!")
elif player == "rock":
if computer == "paper":
lose += 1
print("You lose!")
else:
win += 1
print("You win!")
elif player == "paper":
if computer == "scissors":
lose += 1
print("You lose!")
else:
win += 1
print("You win!")
elif player == "scissors":
if computer == "rock":
lose += 1
print("You lose!")
else:
win += 1
print("You win!")
else:
print("That's not a valid play. Check your spelling!")
print("Final Tally")
print("************")
print("User Wins: ", win)
print("Computer Wins: ", lose)
print("Ties: ", tie)
if tie > win and tie > lose:
print("It's a tie!")
elif win > tie and win > lose:
print("You won!")
else:
print("The computer won!")
更新：顯然我無事可做。好吧，這是一種簡化獲勝條件的直接方法。
win_condition_rock = player == 'rock' and computer == 'scissors'
win_condition_paper = player == 'paper' and computer == 'rock'
win_condition_scissors = player == 'scissors' and computer == 'paper'
if player == computer:
# tie += 1 is the same as tie = tie + 1
tie +=1
print("Tie!")
elif any([win_condition_paper, win_condition_scissors, win_condition_rock]):
win += 1
print('You win')
else:
lose += 1
print('You lose')
更新 2：這是對有效輸入的檢查
while player not in t:
player = input("rock, paper, scissors: ").lower()
if player not in t:
print('Invalid input')
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