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無法正確解碼/編碼 Url

無法正確解碼/編碼 Url

慕少森 2022-12-22 11:53:34
我正在研究一個 Url 解碼和編碼系統。但由于一些奇怪的原因,它只會解碼/編碼特定的字符串。此外,它似乎在字符串中包含特定片段時對其進行解碼/編碼。這很難解釋,但對于這可能行不通的事情卻很困惑。我試著弄清楚它的問題,但這只會讓整個問題看起來更不合邏輯。我希望有人可以幫助我。有解釋。如果代碼與它的風格相同,我會喜歡它。我也知道網上可能有一些軟件包可以輕松做到這一點,但我寧愿自己制作。這是我可以更多地練習 JS 的一種方式。// I know I don't have all the characters markek. I am doing that latervar Url = {  filterEncode : ["%2B","%3A","%3D","%3F","%2F","%26","%252F","%253A","%253D","%253F","%252B"],  filterDecode : ["+",":","=","?","/","&","%2F","%3A","%3D","%3F","%2B"],  decode : function(decodeText){    let returnString, a, b;    let filterEncode = Url.filterEncode;    let filterDecode = Url.filterDecode;    for (a = 0; a < filterEncode.length; a++){      let regexEn = new RegExp(filterEncode[a],"g");      let regexDe = new RegExp("/" + filterDecode[a],"g");      let regex = new RegExp(regexEn,"g");      let array = (decodeText.match(regex) || []).length      for (b = 0; b < array; b++){        returnString = decodeText.replace(filterEncode[a],filterDecode[a]);        decodeText = returnString;      }    }    return returnString;  },  encode : function(encodeText){    let returnString, a, b;    let filterEncode = Url.filterEncode;    let filterDecode = Url.filterDecode;    for (a = 0; a < filterEncode.length; a++){      let regexEn = new RegExp("[" + filterEncode[2] + "]","g");      let regexDe = new RegExp("[" + filterDecode[2] + "]","g");      let regex = new RegExp(regexEn,"g");      let array = (encodeText.match(regex) || []).length;      for (b = 0; b < array; b++){        returnString = encodeText.replace(filterDecode[a],filterEncode[a]);        encodeText = returnString;      }    }    return returnString;  }}// Saying it is undefinedconsole.log(Url.encode("="));// Encodes it just findconsole.log(Url.encode("%3F"));// Encodes both of them but for some odd reason encodes the// equal sign twice.console.log(Url.encode("%3F ="));我確實希望關于我的問題是什么,一切看起來都很清楚。我通常只是嘗試在這里搜索答案,但這個問題太混亂了,我不知道我到底應該搜索什么。
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皈依舞

TA貢獻1851條經驗 獲得超3個贊

您的某些字符串filterDecode作為正則表達式具有特殊含義。將字符串轉換為正則表達式時,需要將每個字符都包裹起來,[]以便按字面意思進行匹配。


/創建regexDe. _


不需要for(b...)循環。在調用中使用正則表達式,replace()它將立即執行所有替換,因為它有g標志。


將包含的編碼字符串放在%數組的開頭。否則,當您對類似=as的內容進行編碼時%3D,外循環的后續迭代會將其重新編碼為%253D。如果它在原始字符串中,而不是中間步驟,您只想對其進行編碼。


var Url = {

  filterDecode: ["%252F", "%253A", "%253D", "%253F", "%252B", "%2B", "%3A", "%3D", "%3F", "%2F", "%26"],

  filterEncode: ["%2F", "%3A", "%3D", "%3F", "%2B", "+", ":", "=", "?", "/", "&"],

  strToRe: function(str) {

    let reStr = str.split("").map(c => '[' + c + ']').join('');

    return new RegExp(reStr, "g");

  },

  decode: function(decodeText) {

    let a;

    let filterEncode = Url.filterEncode;

    let filterDecode = Url.filterDecode;

    for (a = 0; a < filterDecode.length; a++) {

      decodeText = decodeText.replace(Url.strToRe(filterDecode[a]), filterEncode[a]);

    }

    return decodeText;

  },

  encode: function(encodeText) {

    let a, b;

    let filterEncode = Url.filterEncode;

    let filterDecode = Url.filterDecode;

    for (a = 0; a < filterEncode.length; a++) {

      encodeText = encodeText.replace(Url.strToRe(filterEncode[a]), filterDecode[a]);

    }

    return encodeText;

  }

}


console.log(Url.encode("="));

console.log(Url.decode("%3D"));

console.log(Url.encode("%3F"));

console.log(Url.decode("%253F"));

console.log(Url.encode("%3F ="));

console.log(Url.decode("%253F %3D"));


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