我有如下字典x_wins = {'row1_X': 'X' == x_o[0] and 'X' == x_o[1] and 'X' == x_o[2],'row2_X' : 'X' == x_o[3] and 'X' == x_o[4] and 'X' == x_o[5],'row3_X' : 'X' == x_o[6] and 'X' == x_o[7] and 'X' == x_o[8],'col1_X' : 'X' == x_o[0] and 'X' == x_o[3] and 'X' == x_o[6],'col2_X' : 'X' == x_o[1] and 'X' == x_o[4] and 'X' == x_o[7],'col3_X' : 'X' == x_o[2] and 'X' == x_o[5] and 'X' == x_o[8],'slant1_X' : 'X' == x_o[0] and 'X' == x_o[4] and 'X' == x_o[8],'slant2_X' : 'X' == x_o[2] and 'X' == x_o[4] and 'X' == x_o[6]}我想檢查是否有任何鍵給出 True。我該怎么做？謝謝幫助。
3 回答
慕沐林林
TA貢獻2016條經驗 獲得超9個贊
如果我理解正確，您可以使用列表理解來查找“True”鍵：
true_keys = [x for x in x_wins if x_wins[x] == True]
例子：
x_o =['X','X','X',0,0,0,'X','X','X']
x_wins = {'row1_X': 'X' == x_o[0] and 'X' == x_o[1] and 'X' == x_o[2],
'row2_X' : 'X' == x_o[3] and 'X' == x_o[4] and 'X' == x_o[5],
'row3_X' : 'X' == x_o[6] and 'X' == x_o[7] and 'X' == x_o[8],
'col1_X' : 'X' == x_o[0] and 'X' == x_o[3] and 'X' == x_o[6],
'col2_X' : 'X' == x_o[1] and 'X' == x_o[4] and 'X' == x_o[7],
'col3_X' : 'X' == x_o[2] and 'X' == x_o[5] and 'X' == x_o[8],
'slant1_X' : 'X' == x_o[0] and 'X' == x_o[4] and 'X' == x_o[8],
'slant2_X' : 'X' == x_o[2] and 'X' == x_o[4] and 'X' == x_o[6]
}
true_keys = [x for x in x_wins if x_wins[x] == True]
print(true_keys)
輸出：
['row1_X', 'row3_X']
郎朗坤
TA貢獻1921條經驗 獲得超9個贊
您可以檢查任何字典值是否為真：
if True in x_wins.values():
print("Success!")
else:
print("All False...")
你也可以any這樣使用：if any(x_wins.values()): ...
如果要獲取值為 True 的鍵，則：
valid_keys = [key for key, val in x_wins.items() if val is True]
這將給出所有值為 True 的鍵的列表。
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