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將兩個嵌套的 json 對象與 javascript 結合起來，并用一個鍵循環遍歷它

JavaScript

ITMISS 2022-12-18 16:35:49

我有幾個 json 對象（obj1、obj2...），每個對象都取自 .txt 文件：{ "countries": [ { "Country name": "China", "Flag": "CN", "Population": 1395380000, "undefined": "#688144" }, ... ]}和{ "countries": [ { "Country name": "India", "Flag": "IN", "Population": 1338677000, "undefined": "#B78A31" }, ...]}等等。現在我想像這樣組合它們：{ "countries": [ { "Country name": "China", "Flag": "CN", "Population": 1395380000, "undefined": "#688144" }, { "Country name": "India", "Flag": "IN", "Population": 1338677000, "undefined": "#B78A31" }, ... ]}所以我可以像這樣遍歷數據：let obj1 = {}; //saved Data From Txt1;let obj2 = {}; //saved Data From Txt2...let obj = combined?for (var key in obj.countries) {var num1 = obj.countries[key].Population+popholder;if (target >= popholder && target <= num1) { var country = obj.countries[key]['Country name']; var testas = document.getElementById("countryname")}}我怎么能做到這一點？

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3 回答

動漫人物

TA貢獻1815條經驗獲得超10個贊

只需連接數組：

const obj1 = {

"countries": [{

"Country name": "China",

"Flag": "CN",

"Population": 1395380000,

"undefined": "#688144"

}

]

};

const obj2 = {

"countries": [{

"Country name": "India",

"Flag": "IN",

"Population": 1338677000,

"undefined": "#B78A31"

}

]

};

const result = {

countries: [...obj1.countries, ...obj2.countries]

};

console.log(result);

反對回復 2022-12-18

精慕HU

TA貢獻1845條經驗獲得超8個贊

您可以使用創建一個具有相同countries屬性的新對象Array#concat并將所有國家/地區數組合并為一個：

const obj1 = {

"countries": [{

"Country name": "China",

"Flag": "CN",

"Population": 1395380000,

"undefined": "#688144"

}, /* ... */ ]

};

const obj2 = {

"countries": [{

"Country name": "India",

"Flag": "IN",

"Population": 1338677000,

"undefined": "#B78A31"

}, /* ... */ ]

};

const obj3 = {

"countries": [{

"Country name": "Sealand",

"Flag": "",

"Population": 27,

"undefined": "#0000FF"

}, /* ... */ ]

};

const combined = {

countries: [].concat(

obj1.countries,

obj2.countries,

obj3.countries

)

};

console.log(combined);

如果你有一個對象數組，你可以結合Array#map擴展語法來提取countries數組并將它們組合成一個：

const obj1 = { "countries": [{ "Country name": "China", "Flag": "CN", "Population": 1395380000, "undefined": "#688144" }, /* ... */ ]};

const obj2 = { "countries": [{ "Country name": "India", "Flag": "IN", "Population": 1338677000, "undefined": "#B78A31" }, /* ... */ ]};

const obj3 = { "countries": [{ "Country name": "Sealand", "Flag": "", "Population": 27, "undefined": "#0000FF" }, /* ... */ ]};

const objArr = [obj1, obj2, obj3];

const combined = {

combined: [].concat(

...objArr.map(x => x.countries)

)

};

console.log(combined)

反對回復 2022-12-18

胡說叔叔

TA貢獻1804條經驗獲得超8個贊

你可以push所有數組合二為一。

const obj1 = {

"countries": [

{

"Country name": "China",

"Flag": "CN",

"Population": 1395380000,

"undefined": "#688144"

}, ]}

const obj2 = {

"countries": [

{

"Country name": "India",

"Flag": "IN",

"Population": 1338677000,

"undefined": "#B78A31"

},]};

const res = [obj1, obj2, /*...*/]

.reduce((acc,{countries})=>(acc.countries.push(...countries),acc), {countries: []});

console.log(res);

反對回復 2022-12-18

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將兩個嵌套的 json 對象與 javascript 結合起來，并用一個鍵循環遍歷它

將兩個嵌套的 json 對象與 javascript 結合起來，并用一個鍵循環遍歷它

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將兩個嵌套的 json 對象與 javascript 結合起來，并用一個鍵循環遍歷它

將兩個嵌套的 json 對象與 javascript 結合起來，并用一個鍵循環遍歷它