我正在嘗試自定義我的正文錯誤消息。我的springboot版本是2.1.5.RELEASE我要這個：{"This should be application specific"}但我收到這個：{ "timestamp": "2019-05-24T15:47:10.872+0000", "status": 500, "error": "Internal Server Error", "message": "Not Found (404)", "path": "/github/gifojhuinh4w5"}我的異常類是：@ControllerAdvicepublic class AppExceptionHandler extends ResponseEntityExceptionHandler { @ExceptionHandler(Exception.class) protected ResponseEntity<Object> handleConflict(Exception ex, WebRequest request) { String bodyOfResponse = "This should be application specific"; return handleExceptionInternal(ex, bodyOfResponse, new HttpHeaders(), HttpStatus.INTERNAL_SERVER_ERROR, request); }}我的班級捕獲異常@Controller@EnableAutoConfigurationpublic class GitHub { @RequestMapping(value ="/github/{usuario}", produces = "application/json; charset=UTF-8") @ResponseBody public ResponseEntity<Object> quantidadeRepositorios(@PathVariable(value = "usuario")String usuario) throws IOException { HashMap<String, Integer> map = new HashMap<>(); RepositoryService service = new RepositoryService(); GitHubClient client = new GitHubClient(); Gson gson = new Gson(); client.setOAuth2Token("key"); map.put("Total",service.getRepositories(usuario).size()); // exception captured here return new ResponseEntity<>(gson.toJson(map), HttpStatus.OK); }}
1 回答
智慧大石
TA貢獻1946條經驗 獲得超3個贊
當 ExceptionHandler 捕獲到異常時，構建一個響應實體并返回它，如下所示。
創建一個 ErrorResponseDTO 對象并為其設置消息。
public class ErrorResponseDTO {
private String errorMessage;
}
在異常處理程序中，返回該 dto 對象。
@ExceptionHandler(Exception.class)
protected ResponseEntity<Object> handleConflict(Exception ex, WebRequest request) {
ErrorResponseDTO errorDTO = new ErrorResponseDTO();
errorDTO.setErrorMessage("This should be application specific");
return new ResponseEntity<>(errorDTO, HttpStatus.INTERNAL_SERVER_ERROR);
}
這將為您提供您正在尋找的有效載荷。
{
"This should be application specific"
}
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