我是編程新手。我正在嘗試在一個簡單的二十一點游戲中創建一個“命中或停留”功能，在 try/except/else 語句中接受用戶輸入，該語句也嵌套在 while 循環檢查中以確保用戶輸入是“h”或's'。問題是變量永遠不會分配給用戶輸入。這是我所擁有的：def hit_or_stay(deck,hand): global playing x = '' # just holds input for hit/stay while x !='h' and x !='s': try: x = input('HIT or STAY? (h/s): ').lower except: print("Please enter h to hit or s to stay." ) else: break if x == 'h': print("You have chosen to hit.") hit(deck,hand) elif x == 's': print("You have chosen to stay.") playing = False else: print(f"x equals {x}")該程序總是只在末尾返回“else”語句，所以我知道 x 沒有正確接受用戶輸入。我究竟做錯了什么？
1 回答
蕭十郎
TA貢獻1815條經驗 獲得超13個贊
lower是一個你需要像這樣調用的函數。您也不需要else在 while 循環中。
def hit_or_stay(deck,hand):
global playing
x = '' # just holds input for hit/stay
while x !='h' and x !='s':
try:
x = input('HIT or STAY? (h/s): ').lower()
except:
print("Please enter h to hit or s to stay." )
if x == 'h':
print("You have chosen to hit.")
hit(deck,hand)
elif x == 's':
print("You have chosen to stay.")
playing = False
else:
print(f"x equals {x}")
我不確定將try-except塊放在 while 循環中會產生什么行為。這行代碼可能拋出的唯一異常是用戶試圖通過按 Ctrl+C 退出程序。您的代碼會捕捉到這一點并繼續告訴用戶輸入 h 或 s。這通常不是好的行為——最好不要包含 try-except。
def hit_or_stay(deck,hand):
global playing
x = '' # just holds input for hit/stay
while x !='h' and x !='s':
x = input('HIT or STAY? (h/s): ').lower()
if x == 'h':
print("You have chosen to hit.")
hit(deck,hand)
elif x == 's':
print("You have chosen to stay.")
playing = False
else:
print(f"x equals {x}")
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