我想通過字符串數組過濾出對象數組let allUsers = [{  "avatar":null,  "deleted":false,  "_id":"5f1f5df967b3240004f50a36",  "email":"[email protected]",  "password":"$2a$10$5eKv6OVouPnPH.3g9STEYO990V.L14kpD2ImZ3AtZtHaRjCg4oj/6",  "fcm":"fcm3",  "createdAt":"2020-07-27T23:06:33.683Z",  "updatedAt":"2020-07-27T23:06:33.683Z",  "__v":0},{  "avatar":null,  "deleted":false,  "_id":"5f1f5e0067b3240004f50a37",  "email":"[email protected]",  "password":"$2a$10$czA2dASdEo1Dw0oAxw.y1eJwg4lrZW12tLE6sUeG5k.PThuineTIm",  "fcm":"fcm2",  "createdAt":"2020-07-27T23:06:40.702Z",  "updatedAt":"2020-07-27T23:06:40.702Z","__v":0},{  "avatar":null,  "deleted":false,  "_id":"5f1f5d9167b3240004f50a33",  "email":"[email protected]",  "password":"$2a$10$0O2aDCCSibWlNznIWfHTxuY8vNq4Sge/YDRuntKJl9UKnSI.9TEfC",  "fcm":"fcm1",  "createdAt":"2020-07-27T23:04:49.285Z",  "updatedAt":"2020-07-27T23:04:49.285Z",  "__v":0}]let connectedUsers = ['5f1f5df967b3240004f50a36','5f1f5e0067b3240004f50a37']輸出應該是不在第二個數組中的第三個用戶：myArrayFiltered = [  {    "avatar":null,    "deleted":false,    "_id":"5f1f5d9167b3240004f50a33",    "email":"[email protected]",    "password":"$2a$10$0O2aDCCSibWlNznIWfHTxuY8vNq4Sge/YDRuntKJl9UKnSI.9TEfC",    "fcm":"fcm1",    "createdAt":"2020-07-27T23:04:49.285Z",    "updatedAt":"2020-07-27T23:04:49.285Z",    "__v":0  }]我試過了 let myArrayFiltered = allUsers.filter((user) => {    return connectedUsers.some((el) => {      return user._id !== el;    });  });但它返回所有 3 個用戶編輯：所有答案都返回第二個數組中的 2 個用戶，但我想要的是不是用戶，即 ID 為“5f1f5d9167b3240004f50a33”的用戶