我有一個類Tempo。我可以自由改變：public class Tempo{ public Period Period { get; set; } public int Value { get; set; } // in fact int should be a T here if it matters. // more properties here}Period是來自我無法更改的外部依賴項的類。public class Period{ public DateTime Start { get; set; } public DateTime End { get; set; } public int Count { get; set; } public string Foo { get; set; } // more properties here}Period是一個巨大的類，有很多我不想序列化的屬性。所以對我來說沒有甜蜜[JsonIgnore]。從Period我想只保留屬性Start和End。我嘗試使用 aDefaultContractResolver但沒有成功：class TempoResolver : DefaultContractResolver{ protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization) { var props = base.CreateProperties(type, memberSerialization); return props .Where(p => p.PropertyName != "Period") // how to filter subclass? .ToList(); }}我嘗試使用 aJsonConverter但沒有成功：public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer){ var jo = new JObject(); var type = value.GetType(); jo.Add("type", type.Name); foreach (var prop in type.GetProperties().Where(x => x.CanRead)) { object propVal = prop.GetValue(value, null); if (propVal != null) { jo.Add(prop.Name, JToken.FromObject(propVal, serializer)); // how to filter subclass? } } jo.WriteTo(writer);}在這兩種情況下，我都不確定如何過濾Period. 如何在序列化期間忽略我不擁有的子類的屬性？
3 回答
當年話下
TA貢獻1890條經驗 獲得超9個贊
JsonConverter您可以為類創建強類型Period：
public class PeriodConverter : JsonConverter<Period>
{
public override void WriteJson(JsonWriter writer, Period period, JsonSerializer serializer)
{
writer.WriteStartObject();
writer.WritePropertyName(nameof(Period.Start));
writer.WriteValue(period.Start);
writer.WritePropertyName(nameof(Period.End));
writer.WriteValue(period.End);
writer.WriteEndObject();
}
public override Period ReadJson(JsonReader reader, Type objectType, Period existingValue, bool hasExistingValue,
JsonSerializer serializer)
{
throw new NotSupportedException();
}
}
用法：
var tempo = new Tempo
{
Period = new Period
{
Start = DateTime.Now.AddDays(-1),
End = DateTime.Now.AddHours(-1),
Count = 42,
Foo = "Foo"
},
Value = 42
};
var result = JsonConvert.SerializeObject(tempo, new PeriodConverter());
var regularJson = JsonConvert.SerializeObject(tempo);
regularJson將具有以下所有屬性Period：
{"期間":{"開始":"2019-04-08T12:21:39.1525361+03:00","結束":"2019-04-09T11:21:39.1535328+03:00","計數": 42，“富”：“富”}，“值”：42}
并且result只期望：
{"期間":{"開始":"2019-04-08T12:21:39.1525361+03:00","結束":"2019-04-09T11:21:39.1535328+03:00"},"值" :42}
更新
WriteJson可以使用匿名對象簡化代碼：
public override void WriteJson(JsonWriter writer, Period period, JsonSerializer serializer)
{
var token = JToken.FromObject(new {Start = period.Start, End = period.End});
token.WriteTo(writer);
}
慕斯王
TA貢獻1864條經驗 獲得超2個贊
制作子類：
public class Periodic
{
public DateTime Start { get; set; }
public DateTime End { get; set; }
}
使用帶有此代碼的自定義轉換器：
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
Periodic periodic = (Periodic)value;
JToken t = JToken.FromObject(periodic);
t.WriteTo(writer);
}
斯蒂芬大帝
TA貢獻1827條經驗 獲得超8個贊
一種解決方案是使用以下子集Period：
// your external dependency
public class Period
{
public DateTime Start { get; set; }
public DateTime End { get; set; }
public int Count { get; set; }
public string Foo { get; set; }
}
// your copycat with only the properties you really need
public class Periodic
{
public DateTime Start { get; set; }
public DateTime End { get; set; }
}
public class Tempo
{
public Periodic Period { get; set; }
public int Value { get; set; }
}
public static void Main()
{
var period = new Period{Count = 1, Foo = "bar", Start = DateTime.Now, End = DateTime.Now.AddDays(1)};
var tempo = new Tempo{Value = 1, Period = new Periodic {Start = period.Start, End = period.End} };
Console.WriteLine(JsonConvert.SerializeObject(tempo));
}
您還可以使用像Automapper這樣的庫來處理外部類和模仿者之間的映射。對于兩個屬性，它可能有點矯枉過正。
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