我制作了一個數組來隨機選擇“牛排、比薩餅或薯條”，但在運行我的程序時，它在你回答問題之前就出錯了。在給我一個例外之前，它適用于大約 5 個輸入。我認為問題出在{System.out.println(FoodArray.getRandomWord(args));但我似乎無法弄清楚它有什么問題。我只需要我的程序能夠正確運行，當它遇到關于給出隨機建議的問題時，它隨機打印出牛排、比薩餅或薯條。public static void main(String[] args) {    int input = 0;    int sweet = 0;    int savory = 0;    int salty = 0;    Random r = new Random();    FoodArray a = new FoodArray();    Scanner myscanner = new Scanner(System.in);    System.out.println("Welcome, lets figure out what you're hungry for."            + "Press 0 to continue");    input = myscanner.nextInt();    if (input > 0) {    }    {        System.out.println("What sounds the best to you right now?\n"                + "1) Something sweet\n"                + "2) Savory\n "                + "3) Salty\n ");    }    input = myscanner.nextInt();    if (input == 1) {        System.out.println("something sweet. okay. next question");        sweet++;    } else if (input == 2) {        System.out.println("Savory eh? got it. lets move on.");        salty++;    } else if (input == 3) {        System.out.println("Sounds good. Lets proceed");        savory++;    }    System.out.println("Press 0 to continue");    input = myscanner.nextInt();    System.out.println("pick a number 1-3");    input = myscanner.nextInt();    if (input == 1) {        System.out.println("Very interesting.");        sweet++;    } else if (input == 2) {        System.out.println("Very interesting.");        salty++;    } else if (input == 3) {        System.out.println("Very interesting.");        savory++;    }    System.out.println("Press 0 to continue");    input = myscanner.nextInt();    System.out.println("Next question: "            + "Would you rather, fly, (1) breath underwater, (2) or be invisible (3)");    input = myscanner.nextInt();    if (input == 1) {        System.out.println("Good choice.");        sweet++;    }    if (input == 2) {        System.out.println("Would be pretty cool");        salty++;    }