我收到這樣的語法錯誤Uncaught SyntaxError: missing ) after argument list這是代碼 $(document).ready(function(){ $('#jk_id').on('change',function(){ let id = $this.val(); $('#kk_id').empty(); $('#kk_id').append('<option value="0" selected disabled>--- Pilih Komponen Kegiatan ---</option>'); $.ajax({ type:'GET', url:'admin/pengajuan/create1/' + id, success: function(response) { var response = JSON.parse(response); console.log(response); $('#kk_id').empty(); $('#kk_id').append('<option value="0" selected disabled>--- Pilih Komponen Kegiatan ---</option>'); response.forEach(element => { $('#kk_id').append('<option value ="${element['id']}">${element['name']}</option>'); }); } }); });});我是 Jquery 的新手.......................... ...................................
錯誤 Ajax , Jquery Uncaught SyntaxError: missing )
嚕嚕噠
2022-11-11 16:05:11
