我目前正在嘗試導航到另一個網頁，并使用我抓取的超鏈接獲取其 HTML。（我需要存儲在上面的信息）。我目前無法使用我生成的鏈接獲取 PHP curl 函數來獲取 HTML 代碼。我試圖用來構建/獲取 HTML 代碼的代碼部分是：foreach($rows as $row){    //creating the link itself. https://pr.mo.gov/ is the website itself, the attribute that is returend is the direction location.    // /pharmacy-licensee-search-detail.asp?passkey=1285356, us an example of what I get from getArrtibute('href')    $holder = "https://pr.mo.gov/".$row->getAttribute('href');    // $holder = https://pr.mo.gov/pharmacy-licensee-search-detail.asp?passkey=1285356 as per the example used in the comments above.    echo $holder;    echo "<br>";    //trying to use curl to get the website html    $c = curl_init("$holder");    $html2 = curl_exec($c);    //Trying to print out what has been recived    echo var_dump($html2);     //IT's printing out bool(false)    curl_close($c);}這部分之前的代碼工作正常——因為它從原始網頁中獲取了 HTML。如果需要，我會發布它。