我想venue_與venueName. 但似乎它只顯示最后一個venue_結果。知道我的代碼有什么問題嗎？$venueLength = 6;for ($i = 0; $i < $venueLength; $i++) { $linkageArray = array(); $mainArray = array ("venueName" => $venueArray[$i]['venueName']); for ($j = 0; $j < $venueLength; $j++) { $secondArray = array ( "venue_".$j => (in_array($venueArray[$j]['venueID'], $linkageArray) ? 'X' : '')); } $res[] = array_merge($mainArray, $secondArray); } header("Content-type: application/json");$result = json_encode($res);echo $result;結果[ { venueName: "Data A", venue_5: "" }, { venueName: "Data A3", venue_5: "" }, { ........]我想要的結果[ { venueName: "Data A", venue_0: "", venue_1: "", venue_2: "", venue_3: "", venue_4: "", venue_5: "" }, { venueName: "Data A3", venue_0: "", venue_1: "", venue_2: "", venue_3: "", venue_4: "", venue_5: "" }, ........]
1 回答
aluckdog
TA貢獻1847條經驗 獲得超7個贊
您只需繼續重置$secondArray值
$secondArray = array ( "venue_".$j => (in_array($venueArray[$j]['venueID'], $linkageArray) ? 'X' : ''));
而是在循環外重置數組并為每個循環添加一個新值......
$secondArray = [];
for ($j = 0; $j < $venueLength; $j++) {
$secondArray[ "venue_".$j ] = (in_array($venueArray[$j]['venueID'], $linkageArray) ? 'X' : ''));
}
或者直接添加到$mainArray
for ($j = 0; $j < $venueLength; $j++) {
$mainArray[ "venue_".$j ] = (in_array($venueArray[$j]['venueID'], $linkageArray) ? 'X' : ''));
}
你不需要array_merge().
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