我是 tkinter 新手并嘗試了一個簡單的 Tkinter GUI，但出現錯誤：TypeError：“NoneType”對象不可調用這是我的代碼：from tkinter import *from tkinter import filedialogimport pandas as pdimport pyodbcfrom sqlalchemy import create_engineimport urllibmaster = Tk()master.title("Demo GUI")master.geometry("900x400+150+150")master.resizable(0,0)def browse_file(): global file_path global data_frame file_path = filedialog.askopenfilename(title = "Choose the file to upload") data_frame = pd.read_excel(file_path)Label = Label(master,text="Choose the file to upload").grid(row=0)Button = Button(master,text='Browse',command = browse_file).grid(row=0,column=1,pady=4)Label_1 = Label(master,text="The file selected: "+file_path).grid(row=1,column=0)master.mainloop()我得到的錯誤是，TypeError Traceback (most recent call last)<ipython-input-29-451372edd65a> in <module> 25 Button = Button(master,text='Browse',command = browse_file).grid(row=0,column=1,pady=4) 26 ---> 27 Label1 = Label(master,text="The file Choosen: "+file_path).grid(row=1,column=0) 28 29 TypeError: 'NoneType' object is not callable
3 回答
qq_花開花謝_0
TA貢獻1835條經驗 獲得超7個贊
'NoneType' 對象不可調用錯誤是由將對象放置在定義的位置引起的。所以而不是
Label_1 = Label(master,text="The file selected: "+file_path).grid(row=1,column=0)
嘗試：
Label(master,text="The file selected: "+file_path).grid(row=1,column=0)
或者
Label_1 = Label(master,text="The file selected: "+file_path) Label_1.grid(row=1,column=0)
也不要使用 Button = Button(master... 而是給變量一個唯一的名稱
青春有我
TA貢獻1784條經驗 獲得超8個贊
這是答案：
from tkinter import *
from tkinter import filedialog
import tkinter as tk
import pandas as pd
import pyodbc
from sqlalchemy import create_engine
import urllib
master = Tk()
master.title("Demo GUI")
master.geometry("900x400+150+150")
master.resizable(0,0)
def browse_file():
global file_path
global data_frame
file_path = filedialog.askopenfilename(title = "Choose the file to upload")
data_frame = pd.read_excel(file_path)
Label = Label(master,text="Choose the file to upload").grid(row=0)
Button = Button(master,text='Browse',command = browse_file).grid(row=0,column=1,pady=4)
Label_1 = tk.Label(master,text="The file selected: "+file_path).grid(row=1,column=0)
master.mainloop()
30秒到達戰場
TA貢獻1828條經驗 獲得超6個贊
您所做的錯誤是一個錯字：通過編寫：
Label = Label(master,text="Choose the file to upload").grid(row=0)
您將grid調用結果分配給原始 tk.Label 類型 ( Label)。網格回電是None
因此，當您嘗試創建 Label1 時，您實際上是在調用現在的 LabelNone
只需將行替換為：
l = Label(master,text="Choose the file to upload") l.grid(row=0)
或者干脆
Label(master,text="Choose the file to upload").grid(row=0)
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