2 回答

TA貢獻1862條經驗 獲得超7個贊
嘗試這個:
this.cars[index].starred = !this.cars[index].starred;
this.cars.map((i) => {
if(i.name!=this.cars[index].name)
i.starred = false;
});

TA貢獻1829條經驗 獲得超9個贊
我更喜歡先保存目標的“已加星標”狀態,然后再切換它。
如果是這樣,您不需要在 for 循環中放置一條if語句。雖然在這種情況下,它并沒有大大提高性能,但我相信避免太多if from for-loop是一個好習慣。
下面是示例:
new Vue({
el: "#app",
data() {
return {
cars: [{
name: "Toyota",
starred: false
},
{
name: "BMW",
starred: false
},
{
name: "Ford",
starred: false
}
]
};
},
methods: {
setStarred(index) {
let cur = this.cars[index].starred
this.cars.forEach((i) => {
i.starred = false;
});
this.cars[index].starred = !cur;
}
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.5.18/vue.js"></script>
<script src="https://cdn.jsdelivr.net/npm/[email protected]/dist/vuetify.min.js"></script>
<link href="https://cdn.jsdelivr.net/npm/[email protected]/dist/vuetify.min.css" rel="stylesheet" />
<div id="app">
<v-app id="inspire">
<v-container>
<v-layout justify-center column>
<v-flex xs6 v-for="(car,index) in cars" :key="index">
<h2>{{car.name}}
<v-icon :color="car.starred ? 'primary': '' " @click="setStarred(index)">star_border
</v-icon>
</h2>
</v-flex>
</v-layout>
</v-container>
</v-app>
</div>
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