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如何對數組的對象進行分組和分離

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如何對數組的對象進行分組和分離

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繁花不似錦 2022-10-27 15:07:35

如何對來自服務器的數組對象進行分組和分離。像這樣的數組：（MOVINGSTATEs這表示停止和m移動。XPOINT 和 YPOINT 這表示汽車的經緯度。）[{MOVINGSTATE: "s",XPOINT:53.9172866,YPOINT: 26.518275},{MOVINGSTATE: "s",XPOINT: 53.9172866,YPOINT: 26.518275},{MOVINGSTATE: "m",XPOINT: 54.0215383,YPOINT: 26.5275599},{MOVINGSTATE: "m",XPOINT: 54.0102666,YPOINT: 26.4989583},{MOVINGSTATE: "s",XPOINT: 54.0016599,YPOINT: 26.5478316},..]我想如果一些MOVINGSTATEContinuous sgoto new array 以及何時MOVINGSTATE更改為mgoto new array 并再次MOVINGSTATE更改為s goto new array。另一個主數組的所有這些新數組對象。我用loadashvar aaa = _loadash.groupBy(props,'MOVINGSTATE')但輸出這個：{m:Array(2),s:Array(3)}我想要這樣的輸出：[ [ {MOVINGSTATE: "s",XPOINT:53.9172866,YPOINT: 26.518275}, {MOVINGSTATE: "s",XPOINT: 53.9172866,YPOINT: 26.518275} ], [ {MOVINGSTATE: "m",XPOINT: 54.0215383,YPOINT: 26.5275599}, {MOVINGSTATE: "m",XPOINT: 54.0102666,YPOINT: 26.4989583} ], [ {MOVINGSTATE: "s",XPOINT: 54.0016599,YPOINT: 26.5478316} ]]謝謝你的幫助

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1 回答

慕萊塢森

TA貢獻1810條經驗獲得超4個贊

嘗試這個：

let arr =

[{MOVINGSTATE: "s",XPOINT:53.9172866,YPOINT: 26.518275},

{MOVINGSTATE: "s",XPOINT: 53.9172866,YPOINT: 26.518275},

{MOVINGSTATE: "m",XPOINT: 54.0215383,YPOINT: 26.5275599},

{MOVINGSTATE: "m",XPOINT: 54.0102666,YPOINT: 26.4989583},

{MOVINGSTATE: "s",XPOINT: 54.0016599,YPOINT: 26.5478316}];

let result = arr.reduce( (accumulator, cur) => {

const key = cur["MOVINGSTATE"];

const keyExists = accumulator.find(obj => obj.key === key);

if (!keyExists) {

accumulator.push({key,value:[cur]});

return accumulator;

} else if(accumulator[accumulator.length -1] && accumulator[accumulator.length -1].key === key){

accumulator[accumulator.length -1].value.push(cur);

return accumulator;

} else {

accumulator.push({key,value:[cur]});

return accumulator;

}

}, [])

.map(obj => obj.value)

反對回復 2022-10-27

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如何對數組的對象進行分組和分離

如何對數組的對象進行分組和分離

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