我正在嘗試在我的程序中實現另一個條件，但似乎無法弄清楚。這是代碼：print ("Welcome to the winning card program.")year_one=[]year_one.append(eval(input("Enter the salary individual 1 got in year 1: ")))year_one.append(eval(input("Enter the salary individual 2 got in year 1: "))) if year_one[0]==year_one[1]: print("Error. The amount are the same, please reenter information.")year_two=[]year_two.append(eval(input("Enter the salary individual 1 got in year 2: ")))year_two.append(eval(input("Enter the salary individual 2 got in year 2: "))) if year_two[0]==year_two[1]: print("Error. The amount are the same, please reenter information.")year_three=[]year_three.append(eval(input("Enter the salary individual 1 got in year 3: ")))year_three.append(eval(input("Enter the salary individual 2 got in year 3: "))) if year_three[0]==year_three[1]: print("Error. The amount are the same, please reenter information.")year_four=[]year_four.append(eval(input("Enter the salary individual 1 got in year 4: ")))year_four.append(eval(input("Enter the salary individual 2 got in year 4: "))) if year_four[0]==year_four[1]: print("Error. The amount are the same, please reenter information.")year_five=[]year_five.append(eval(input("Enter the salary individual 1 got in year 4: ")))year_five.append(eval(input("Enter the salary individual 2 got in year 4: "))) if year_five[0]==year_five[1]: print("Error. The amount are the same, please reenter information.")individual1_total=year_one[0]+year_two[0]+year_three[0]+year_four[0]+year_five[0]individual2_total=year_one[1]+year_two[1]+year_three[1]+year_four[1]+year_five[1] if (individual1_total>individual2_total): print("Individual one has the highest salary.") elif (individual2_total>individual1_total): print("Individual two has the highest salary.")如果兩個人在某一年的薪水完全相同，您應該打印一個錯誤并讓用戶再次輸入該年的薪水。（條件是工資不應該完全相同）。我期待大家的反饋。先感謝您。
2 回答
不負相思意
TA貢獻1777條經驗 獲得超10個贊
好的，所以在這里建立 Surge10 可以更完整地替換您的代碼。我將所有部分分解為函數，并制作了一個字典作為我的內存數據庫。
total_years = 5
years = {}
def dict_key(year, userId):
return '{}:{}'.format(year, userId)
def get_user_data(year, userId):
key = dict_key(year, userId)
years[key] = float(input("Enter the salary individual {} got in year {}:".format(userId, year)))
def get_year_salaray(year, userId):
key = dict_key(year, userId)
return years[key]
def any_salaries_match(year, userIds):
for userLeft in userIds:
salary_left = get_year_salaray(year, userLeft)
for userRight in userIds:
if userLeft != userRight:
salary_right = get_year_salaray(year, userRight)
if salary_left == salary_right:
return True
def get_user_totals(userId):
total = 0
for key, value in years.items():
if ':{}'.format(userId) in key:
total += value
return total
for x in range(total_years):
year = x + 1
data_invalid = True
while data_invalid:
userOne = 1
userTwo = 2
get_user_data(year, userOne)
get_user_data(year, userTwo)
if any_salaries_match(year, [userOne, userTwo]):
print("Error. The amount are the same, please reenter information.")
else:
data_invalid = False
userOneTotal = get_user_totals(1)
userTwoTotal = get_user_totals(2)
if (userOneTotal>userTwoTotal):
print("Individual one has the highest salary.")
elif (userTwoTotal>userOneTotal):
print("Individual two has the highest salary.")
守著一只汪
TA貢獻1872條經驗 獲得超4個贊
因為我們檢查了五個不同的年份，所以我對這五年使用了一個循環。稍后我們可以將它恢復到各個年份。
print ("Welcome to the winning card program.")
years=[]
for x in range(5):
# range starts at zero so add one all the time
# to start it at one
y = str(x + 1)
errors = True
while errors:
salary_one = input("Enter the salary individual 1 got in year " + y + ": ")
salary_two = input("Enter the salary individual 2 got in year " + y + ": ")
if salary_one == salary_two:
print("Error. The amount are the same, please reenter information.")
errors = True
else:
years.append([salary_one, salary_two])
errors = False
year_one = years[0]
year_two = years[1]
...
print(year_one)
print(year_two)
...
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