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從具有常見值的字典中獲取 TKey,其中 TValue 為 List<string>

從具有常見值的字典中獲取 TKey,其中 TValue 為 List<string>

C#
RISEBY 2022-10-23 16:43:25
我有一本看起來像這樣的字典:Dictionary<string, List<string>> dict = new Dictionary<string, List<string>>(){    {"a" , new List<string> { "Red","Yellow"} },    {"b" , new List<string> { "Blue","Red"} },    {"c" , new List<string> { "Green","Orange"} },    {"d" , new List<string> { "Black","Green"} },};我需要作為字典輸出,dict其中的公共值List<string>應該是鍵,值應該是鍵列表。例如:Red: [a,b]Green: [c,d]我不知道如何用listin dictionaryas解決這個問題TValue。請解釋我如何處理字典中的列表。
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2 回答

?
楊__羊羊

TA貢獻1943條經驗 獲得超7個贊

您可以用扁平化您的字典SelectMany并獲得看起來像的簡單列表


"a" - "Red"

"a" - "Yellow"

"b" - "Blue"

"b" = "Red"

// and so on

然后按值分組并從這些組中構建一個新字典。試試這個代碼:


var commonValues = dict.SelectMany(kv => kv.Value.Select(v => new {key = kv.Key, value = v}))

    .GroupBy(x => x.value)

    .Where(g => g.Count() > 1)

    .ToDictionary(g => g.Key, g => g.Select(x => x.key).ToList());


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墨色風雨

TA貢獻1853條經驗 獲得超6個贊

很多循環......循環遍歷字典,然后循環遍歷列表中的每個值。


var result = new Dictionary<string, List<string>>();


// Loop through each key/value pair in the dictionary

foreach (var kvp in dict)

{

    // kvp.Key is the key ("a", "b", etc)

    // kvp.Value is the list of values ("Red", "Yellow", etc)


    // Loop through each of the values

    foreach (var value in kvp.Value)

    {

        // See if our results dictionary already has an entry for this

        // value. If so, grab the corresponding list of keys. If not,

        // create a new list of keys and insert it.

        if (!result.TryGetValue(value, out var list))

        {

            list = new List<string>();

            result.Add(value, list);

        }


        // Add our key to this list of keys

        list.Add(kvp.Key);

    }

}

如果您想通過包含多個項目的條目來過濾它,那么您可以執行以下操作:


result = result.Where(x => x.Value.Count > 1).ToDictionary(x => x.Key, x => x.Value);

或者,您可以避免循環并改用 Linq:


// Flatten the dictionary into a set of tuples

// e.g. (a, Red), (a, Yellow), (b, Blue), (b, Red), etc

var result = dict.SelectMany(kvp => kvp.Value.Select(color => (key: kvp.Key, color)))

    // Group by the value, taking the color as the elements of the group

    // e.g. (Red, (a, b)), (Yellow, (a)), etc

    .GroupBy(item => item.color, item => item.key)

    // Filter to the ones with more than one item

    .Where(group => group.Count() > 1)

    // Turn it into a dictionary, taking the key of the grouping

    // (Red, Green, etc), as the dictionary key

    .ToDictionary(group => group.Key, group => group.ToList());

您還可以使用 linq 查詢語法,該語法稍長,但避免了SelectMany:


var result =

    (

        from kvp in dict

        from color in kvp.Value

        group kvp.Key by color into grp

        where grp.Count() > 1

        select grp

    ).ToDictionary(grp => grp.Key, grp => grp.ToList());


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