亚洲在线久爱草,狠狠天天香蕉网,天天搞日日干久草,伊人亚洲日本欧美

為了賬號安全,請及時綁定郵箱和手機立即綁定
已解決430363個問題,去搜搜看,總會有你想問的

如何在準備好的 SELECT 語句中檢查 NULL 列,然后做一些事情?

如何在準備好的 SELECT 語句中檢查 NULL 列,然后做一些事情?

PHP
拉莫斯之舞 2022-10-22 16:50:34
這是當前代碼,但它所做的只是從 1 行中選擇列。<?phpsession_start();include 'sqlconnection.php';$conn = OpenCon();$stmt = $conn->prepare('SELECT uid,coverphoto,profilepic,bio FROM profile WHERE uid = ?');$stmt->bind_param('i', $_SESSION['uid']);$stmt->execute();$stmt->bind_result($uid,$coverphoto,$profilepic,$bio);while($stmt->fetch()) {    $output=array(        'uid' => $uid,        'coverphoto' => $coverphoto,        'profilepic' => $profilepic,        'bio' => $bio    );}$json=json_encode($output);echo $json;$stmt->close();CloseCon($conn);?>如何為此添加 if 語句,以便如果 coverphoto 和/或 profilepic = null,手動將值分配給輸出數組的 coverphoto 和 profilepic?我將在下面顯示我的錯誤嘗試:<?phpsession_start();include 'sqlconnection.php';$conn = OpenCon();$stmt = $conn->prepare('SELECT uid,coverphoto,profilepic,bio FROM profile WHERE uid = ?');$stmt->bind_param('i', $_SESSION['uid']);if ($stmt->execute()){   if (coverphoto=null){     $coverphoto = 'coverphoto.jpg';    }else{     if (profilepic=null){     $profilepic = "profilepic.jpg";    }else{$stmt->bind_result($uid,$coverphoto,$profilepic,$bio);while($stmt->fetch()) {    $output=array(        'uid' => $uid,        'coverphoto' => $coverphoto,        'profilepic' => $profilepic,        'bio' => $bio    );}}}}$json=json_encode($output);echo $json;$stmt->close();CloseCon($conn);?>
查看完整描述

1 回答

?
牛魔王的故事

TA貢獻1830條經驗 獲得超3個贊

我認為你只是有一些語法錯誤。


<?php

session_start();

include 'sqlconnection.php';

$conn = OpenCon();


$stmt = $conn->prepare('SELECT uid,coverphoto,profilepic,bio FROM profile WHERE uid = ?');

$stmt->bind_param('i', $_SESSION['uid']);

$result = $stmt->execute();

if ($result){

   if ($result['coverphoto']){

     $coverphoto = 'coverphoto.jpg';

    }else{

     if ($result['profilepic']){

     $profilepic = "profilepic.jpg";

    }else{

$stmt->bind_result($uid,$coverphoto,$profilepic,$bio);

while($stmt->fetch()) {

    $output=array(

        'uid' => $uid,

        'coverphoto' => $coverphoto,

        'profilepic' => $profilepic,

        'bio' => $bio

    );

}

}

}

}

$json=json_encode($output);

echo $json;

$stmt->close();

CloseCon($conn);

?>

你也可以這樣做


<?php

<?php

session_start();

include 'sqlconnection.php';

$conn = OpenCon();


$stmt = $conn->prepare('SELECT uid,coverphoto,profilepic,bio FROM profile WHERE uid = ?');

$stmt->bind_param('i', $_SESSION['uid']);

$stmt->execute();

$stmt->bind_result($uid,$coverphoto,$profilepic,$bio);

while($stmt->fetch()) {

    $output=array(

        'uid' => $uid,

        'coverphoto' => $coverphoto ? $coverphio : 'coverphoto.jpg',

        'profilepic' => $profilepic ? $profilepic : 'profilepic.jpg',

        'bio' => $bio

    );

}

$json=json_encode($output);

echo $json;

$stmt->close();

CloseCon($conn);

?>


查看完整回答
反對 回復 2022-10-22
  • 1 回答
  • 0 關注
  • 94 瀏覽

添加回答

舉報

0/150
提交
取消
微信客服

購課補貼
聯系客服咨詢優惠詳情

幫助反饋 APP下載

慕課網APP
您的移動學習伙伴

公眾號

掃描二維碼
關注慕課網微信公眾號