編寫一個程序，提示輸入三角形的邊長并報告三個角。我沒有得到等于180的角度，并且在某些情況下，我得到NaN的某些角度值。我的代碼如下所示public static int getSideA() { System.out.println("What is the length of side a?"); Scanner console = new Scanner(System.in); int a = console.nextInt(); return a;}public static int getSideB() { System.out.println("What is the length of side b?"); Scanner console = new Scanner(System.in); int b = console.nextInt(); return b;}public static int getSideC() { System.out.println("What is the length of side C"); Scanner console = new Scanner(System.in); int c = console.nextInt(); return c;}public static void giveSides(int a, int b, int c) { double angleA = Math.toDegrees(Math.acos((a^2 - b^2 - c^2) / (-2.0 * c * b))); double angleB = Math.toDegrees(Math.acos((b^2 - a^2 - c^2) / (-2.0 * a * c))); double angleC = Math.toDegrees(Math.acos((c^2 - a^2 - b^2) / (-2.0 * a * b))); System.out.println("The three angles are: " + angleA + " " + angleB + " " + angleC);}public static void main(String[] args) { int a = getSideA(); int b = getSideB(); int c = getSideC(); giveSides(a, b, c);}
1 回答
胡說叔叔
TA貢獻1804條經驗 獲得超8個贊
問題在于這三行：
double angleA = Math.toDegrees(Math.acos((a^2 - b^2 - c^2) / (-2.0 * c * b)));
double angleB = Math.toDegrees(Math.acos((b^2 - a^2 - c^2) / (-2.0 * a * c)));
double angleC = Math.toDegrees(Math.acos((c^2 - a^2 - b^2) / (-2.0 * a * b)));
^2并不意味著“平方”。它的意思是“按位異或 2”。您需要使用a*a或Math.pow(a, 2)表示“平方”。
所以這三行應該是：
double angleA = Math.toDegrees(Math.acos((a*a - b*b - c*c) / (-2.0 * c * b)));
double angleB = Math.toDegrees(Math.acos((b*b - a*a - c*c) / (-2.0 * a * c)));
double angleC = Math.toDegrees(Math.acos((c*c - a*a - b*b) / (-2.0 * a * b)));
此外，這些getSideX方法可以合并為一個，并且可以將掃描儀提取到類級別：
static Scanner console = new Scanner(System.in);
public static int getSide(String name) {
System.out.println("What is the length of side " + name + "?");
int a = console.nextInt();
return a;
}
您的main方法現在如下所示：
public static void main(String[] args) {
int a = getSide("A");
int b = getSide("B");
int c = getSide("C");
giveSides(a, b, c);
}
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