我想使用 @ExceptionHandler 來處理任何 Hibernate 異常。如果異常不是 Hibernate 異常，則運行時錯誤的 @ExceptionHandler 會處理異常。問題是，運行時異?？偸莾炏扔?Hibernate 異常處理程序。意思是，發生的任何休眠異常都由通用運行時異常處理程序處理。如何確保 Hibernate 異常由其異常處理程序處理，而不是由運行時異常處理？ '@ExceptionHandler(HibernateException.class)public String handleHibernateException(HibernateException exc, Model theModel) { String message = "An error has occured: " + exc.getLocalizedMessage() + "\n" + exc.getCause().toString() + "\r\n"; myLogger.warning(message); theModel.addAttribute("exception", message); return "testing";}// handle any other runtime/unchecked exception and log it@ExceptionHandler(RuntimeException.class)public String handleRuntimeExceptions(RuntimeException exc, Model theModel) { String message = "An error has occured: " + exc.getLocalizedMessage() + "\n" + exc.getCause().toString() + "\r\n"; myLogger.warning(message); theModel.addAttribute("exception", message); return "testing";}'
1 回答
一只萌萌小番薯
TA貢獻1795條經驗 獲得超7個贊
您可以通過以下方式檢查異常是否是 HibernateException 的實例：
@ExceptionHandler(RuntimeException.class)
public String handleRuntimeExceptions(RuntimeException exc, Model theModel) {
if (exc instanceof HibernateException) {
return handleHibernateException((HibernateException) exc.getCause(), theModel);
} else if (exc.getCause() instanceof HibernateException) {
HibernateException hibernateException = (HibernateException) exc.getCause();
return handleHibernateException(hibernateException, theModel);
}
String message = "An error has occurred: " + exc.getLocalizedMessage() + "\n" + exc.getCause().toString() + "\r\n";
myLogger.warning(message);
theModel.addAttribute("exception", message);
return "testing";
}
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