我想像這樣創建 JSON：{ "name": "val1", "version": "val2", "type": "val3", "settings": [ "setting1, "setting2", "setting3", [ "option1", "option2" ] ]}但我不知道如何在里面創建嵌套數組settings：package mainimport ( "encoding/json" "fmt")type Config struct { Name string `json:"name"` Version string `json:"version"` Type string `json:"type"` Settings []string `json:"settings"`}func main() { settings := []string{"setting1", "setting2", "setting3"} options := []string{"option1", "option2"} setopts := append(settings, options...) c := &Config{"val1", "val2", "val3", setopts} j, err := json.Marshal(c) if err != nil { panic(err) } fmt.Println(string(j))}輸出通過 jq 管道傳輸以提高可讀性：$ ./main | jq{ "name": "val1", "version": "val2", "type": "val3", "settings": [ "setting1", "setting2", "setting3", "option1", "option2" ]}結果是option1和option2是數組內的值settings，但它們應該在嵌套數組內settings。此外，編組時選項可能并不總是存在，在這些情況下不應創建嵌套數組。我怎樣才能做到這一點？
1 回答
慕蓋茨4494581
TA貢獻1850條經驗 獲得超11個贊
您在此處顯示的輸出：
"setting1",
"setting2",
"setting3",
[
"option1",
"option2"
]
可以描述為 JSON 字符串或字符串數組。
您可以使用 來建模，并附[]interface{}加到字符串或切片：
type Config struct {
Name string `json:"name"`
Version string `json:"version"`
Type string `json:"type"`
Settings []interface{} `json:"settings"`
}
func main() {
settings := []interface{}{
"setting1",
"setting2",
"setting3",
[]string{"option1", "option2"},
}
c := &Config{"val1", "val2", "val3", settings}
j, err := json.Marshal(c)
if err != nil {
panic(err)
}
fmt.Println(string(j))
}
游樂場：https ://go.dev/play/p/8LPAVBPmd8w
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