我有一個從數據庫中查找結果的函數。我正在使用while loopwithmysqli_fetch_assoc()從數據庫中獲取結果。但是頁面一直在加載并且沒有顯示任何錯誤。環形  <?php while ($job = mysqli_fetch_assoc(find_all_jobs())) { ?>  <tr class="custom-table-body-titles">    <td><?php echo $job['updated-at']; ?></td>    <td>      <a href="#" class="text-dark"><?php echo $job['title']; ?></a>    </td>                    <td>0/<?php echo $job['required_freelancers']; ?></td>    <td><?php echo $job['delivery_time']; ?> Days</td>    <td>$<?php echo $job['budget']; ?></td>    <td>      <a href="job_details.html" class="btn btn-sm btn-primary">Apply</a>    </td>  </tr>  <?php } ?>功能function find_all_jobs() {  global $connection;  $sql = "SELECT * FROM jobs ORDER BY job_id DESC LIMIT 10";  $stmt = mysqli_stmt_init($connection);  mysqli_stmt_prepare($stmt, $sql);  $result = mysqli_stmt_execute($stmt);  if(!$result) {    die("Database query failed." . mysqli_stmt_error($stmt));  }  return mysqli_stmt_get_result($stmt);  mysqli_stmt_close($stmt);  }