本質上，該程序的目的是將學生信息寫入文件并從同一文件中讀取。該程序包含一個 if 語句，用于判斷學生是否處于良好的信譽或學術試用期，每個文件都有各自的文件（goodstanding.txt 和 probation.txt）。如果我注釋掉 goodstanding.txt 的讀取邏輯，程序工作文件，但對我來說，除了文件路徑之外，它們似乎幾乎相同，顯然。我查看了其他問題，但其中大多數似乎與錯誤的類型轉換有關。它拋出的具體錯誤NumberFormatException For input string: ""在線ID = Integer.parseInt(array[0]);寫邏輯如下：if(GPA >= 2.0) //If GPA >= 2.0, write to good standing file. This is                identical to probation writer, but causes an issue somewhere{     String result = ID + "," + fname + " " + lname + "," + GPA;     OutputStream out = new BufferedOutputStream(Files.newOutputStream(good,      StandardOpenOption.CREATE));     BufferedWriter wt = new BufferedWriter(new OutputStreamWriter(out));     wt.write(result, 0, result.length()); //Write to file from position 0 to                                         length     wt.newLine();     System.out.println("Please enter next WIN or 999 to quit: ");     ID = input.nextInt();     input.nextLine();     wt.close();}     if(GPA < 2.0) //If GPA < 2.0, write to probation file {     String result = ID + "," + fname + " " + lname + "," + GPA;     OutputStream out = new                    BufferedOutputStream(Files.newOutputStream(probation,                    StandardOpenOption.CREATE));     BufferedWriter wt = new BufferedWriter(new OutputStreamWriter(out));     wt.write(result, 0, result.length());     wt.newLine();     System.out.println("Please enter next WIN or 999 to quit: ");     ID = input.nextInt();     input.nextLine();     wt.close();}和讀取邏輯：try{    while(line != null){    array = line.split(",");    ID = Integer.parseInt(array[0]);    name = array[1];    GPA = Double.parseDouble(array[2]);    double ahead = GPA - 2;    System.out.println("WIN: " + ID + " | " + " Name: " + name + " |" + " GPA                                         = " + GPA + " | Ahead by " + ahead);    line = reader.readLine(); }}我也嘗試在 ID 上使用 trim() 方法，但異常仍然存在。是否有一個我需要閱讀更多的概念來解釋這一點？