我有數組：$array = [ 0 => [ 0 => 1500 1 => 994 2 => 155 3 => 530 ] 1 => [ 0 => 1500 1 => 994 2 => 9314 3 => 11 ] 2 => [ 0 => 25 1 => 5 2 => 63 3 => 47 ] 3 => [ 0 => 1500 1 => 994 2 => 3 3 => 51 ]];如果$array[key][0]and$array[key][1]具有相同的值，那么我只需要對重復的 and進行求和$array[key][2]，然后組合成一個鍵。$array[key][3]$array[key][0]$array[key][1]這就是我想要實現的目標：$array = [ 0 => [ 0 => 1500 1 => 994 2 => 9472 3 => 592 ] 1 => [ 0 => 25 1 => 5 2 => 63 3 => 47 ]];第一個和第二個值（1500 和 994）必須保持不變。感謝您的回答！
1 回答
料青山看我應如是
TA貢獻1772條經驗 獲得超8個贊
$array = [
0 => [
0 => 1500,
1 => 994,
2 => 155,
3 => 530,
],
1 => [
0 => 1500,
1 => 994,
2 => 9314,
3 => 11,
],
2 => [
0 => 25,
1 => 5,
2 => 63,
3 => 47,
],
3 => [
0 => 1500,
1 => 994,
2 => 3,
3 => 51,
],];
// create composite array key
$newArray = [];
foreach($array as $item) {
$compositeKey = $item[0] . '-' . $item[1];
$newArray[$compositeKey] = [
$item[0],
$item[1],
isset($newArray[$compositeKey][2]) ? $newArray[$compositeKey][2] + $item[2] : $item[2],
isset($newArray[$compositeKey][3]) ? $newArray[$compositeKey][3] + $item[3] : $item[3],
];
}
echo '<pre>';
print_r(array_values($newArray));
echo '</pre>';
輸出：
Array
(
[0] => Array
(
[0] => 1500
[1] => 994
[2] => 9472
[3] => 592
)
[1] => Array
(
[0] => 25
[1] => 5
[2] => 63
[3] => 47
)
)
http://sandbox.onlinephpfunctions.com/code/940f06c43338d9785b7c47548a0dcbf6e4b2cd75
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