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如何使用字符串類型對象的鍵值對對象數組進行排序

JavaScript

尚方寶劍之說 2022-10-08 17:17:23

我有一個這樣的數組 let years =[ {id: 3, name: "2016", age: "None"}, {id: 1, name: "2017", age: "None"}, {id: 2, name: "2015", age: "None"}, {id: 5, name: "2018", age: "None"}, {id: 3, name: "2018/2019", age: "None"} ] years.sort((c1, c2) => { return c2.name - c1.name; }); console.log(years); 我無法處理這種“2018/2017”方式我該怎么做最好的方法是什么

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4 回答

MM們

TA貢獻1886條經驗獲得超2個贊

您可以使用localeCompare

const years = [

{ id: 3, name: '2016', age: 'None' },

{ id: 1, name: '2017', age: 'None' },

{ id: 2, name: '2015', age: 'None' },

{ id: 5, name: '2018', age: 'None' },

{ id: 3, name: '2018/2019', age: 'None' },

];

years.sort((c1, c2) => c2.name.localeCompare(c1.name));

console.log(years);

反對回復 2022-10-08

Qyouu

TA貢獻1786條經驗獲得超11個贊

你快到了...只需在排序回調中稍作改動，就完成了::

let years = [

{ id: 3, name: '2016', age: 'None' },

{ id: 1, name: '2017', age: 'None' },

{ id: 2, name: '2015', age: 'None' },

{ id: 5, name: '2018', age: 'None' },

{ id: 3, name: '2018/2019', age: 'None' },

];

years.sort((c1, c2) => {

var n1 = c1.name;

var n2 = c2.name;

if(n1 > n2){return -1;

}else if(n2 > n1){ return 1;

}else{return 0;}

});

console.log(years);

反對回復 2022-10-08

慕容森

TA貢獻1853條經驗獲得超18個贊

你可以使用 lodash_.sortBy

var years =

[{id: 5, name: "2018", age: "None"},

{id: 3, name: "2018/2017", age: "None"},

{id: 1, name: "2017", age: "None"},

{id: 3, name: "2016", age: "None"},

{id: 2, name: "2015", age: "None"}]

_.sortBy(years, ['name']);

輸出將是

反對回復 2022-10-08

紅糖糍粑

TA貢獻1815條經驗獲得超6個贊

嘗試這個：

years.sort((c1, c2) => {

if (c1.name > c2.name) return -1;

if (c1.name < c2.name) return 1;

return 0;

});

反對回復 2022-10-08

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如何使用字符串類型對象的鍵值對對象數組進行排序

如何使用字符串類型對象的鍵值對對象數組進行排序

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