我有一個 JSON 對象如下{ "mandator":"GB0010001", "debitAccount":"81884", "creditAccount":"82918", "trustedBeneficiary":"false", "localCurrencyAmount":35, "transactionReference":"omega7.1.1", "debitAccountASPSP":"t24", "currencyAmount":35, "executionDate":"20180102", "creditAccountASPSP":"t24", "transactionType":"Contactless payment", "trustedPSP":"false", "jsonErrorResponse":{ "errorCount":0, "errors":[ ] }, "currency":"USD", "company":"GB0010001"}我需要刪除"jsonErrorResponse":{"errorCount":0,"errors":[]}，我用過JSONobject.remove("jsonErrorResponse").toString()但它給了我輸出{"errorCount":0,"errors":[]}而不是{ "mandator":"GB0010001", "debitAccount":"81884", "creditAccount":"82918", "trustedBeneficiary":"false", "localCurrencyAmount":35, "transactionReference":"omega7.1.1", "debitAccountASPSP":"t24", "currencyAmount":35, "executionDate":"20180102", "creditAccountASPSP":"t24", "transactionType":"Contactless payment", "trustedPSP":"false", "currency":"USD", "company":"GB0010001"}
3 回答
滄海一幻覺
TA貢獻1824條經驗 獲得超5個贊
JSONobject.remove("jsonErrorResponse")返回被移除的東西。您正在調用toString您剛剛“刪除”的部分。
簡單地不要鏈接方法調用。
JSONobject.remove("jsonErrorResponse");
String newJson = JSONobject.toString()
偶然的你
TA貢獻1841條經驗 獲得超3個贊
由于您正在處理，因此JSONobject您正在從該對象中刪除內容。
您需要調用toString().JSONobject
String str = "{\"mandator\":\"GB0010001\",\"debitAccount\":\"81884\",\"creditAccount\":\"82918\",\"trustedBeneficiary\":\"false\",\"localCurrencyAmount\":35,\"transactionReference\":\"omega7.1.1\",\"debitAccountASPSP\":\"t24\",\"currencyAmount\":35,\"executionDate\":\"20180102\",\"creditAccountASPSP\":\"t24\",\"transactionType\":\"Contactless payment\",\"trustedPSP\":\"false\",\"jsonErrorResponse\":{\"errorCount\":0,\"errors\":[]},\"currency\":\"USD\",\"company\":\"GB0010001\"}"
JSONObject jsonObject = new JSONObject(str);
jsonObject.remove("jsonErrorResponse");
jsonObject.toString();
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