所以基本上，如果輸入是1，我需要在我的數組中打印12個給定的數字，如果輸入是2，我需要打印隨機數。格式應如下所示，一行8，塊間距為5，底部為4。1 2 3 4 5 6 7 89 10 11 12all the 12 numbers will be in the same array but the output must be like
this.and if the input is 2, the array must output 12 random numbers all i know and read in the book is something like this to print nomally System.out.printf(Arrays.toString(array)); if (i == 1){ System.out.printf("%5s", Arrays.toString(array)) ; } int i = input.nextInt(); int[] array = {1,2,3,4,5,6,7,8,9,10,11,12}; System.out.printf(Arrays.toString(array)); if (i == 1){ System.out.printf("%5s", Arrays.toString(array)) ; } I wanted the print to be >1 2 3 4 5 6 7 8 /n 9 10 11 12 but the output is within sets {}
2 回答
嗶嗶one
TA貢獻1854條經驗 獲得超8個贊
您可以不用這種方式進行核心打?。篿f
public class TTest1 {
public static void main(String... args) {
int[] array = {1,2,3,4,5,6,7,8,9,10,11,12};
for (int i = 0 ; i < array.length ; i++)
System.out.printf("%5d%s", array[i], (i % 8 == 7)? "\n\n" : "");
System.out.println();
}
}
結果：
1 2 3 4 5 6 7 8
9 10 11 12
忽然笑
TA貢獻1806條經驗 獲得超5個贊
您可以使用掃描儀從用戶處獲取輸入：
Scanner input = new Scanner(System.in);
int i = input.nextInt();
if(i == 1) {
int[] array = {1,2,3,4,5,6,7,8,9,10,11,12};
for(int ind = 0; ind < array.length; ind++) {
System.out.printf("%5d ", array[ind]);
if(ind == 7) {
System.out.println(); //to have 8 numbers on the first line
}
}
}
else {
//write code for random number generation here
}
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