我正在嘗試將循環輸出保存到一個數組中。如果我控制臺.log(arr2),我得到了我想要的結果,但在多個數組中。我想把所有這些東西都放在一個數組中。當我嘗試使用 .push 時,所有數組都會產生相同的值。也許我可以以其他方式做到這一點,但我不知道該怎么做。 let b = {}; let arr3 = []; let arr1 = [{value1: 123, value2: 34, value3: 90, value4: 23, value5: 32},{value1: 10, value2: 09, value3: 54, value4: 32, value5: 311}]; for (let a = 0; a <=4; a++){ b = {"value1": a*a, "value3": a+12, "value4": a/2}; arr2 = arr1.map(function(record){ record.value1 = b.value1; record.value3 = b.value3; record.value4 = b.value4; return record; }) // console.log(arr2); arr3.push(arr2);}console.log(arr3);這就是我用.push完成的,這不是我想要的。 [ { value1: 0, value2: 34, value3: 12, value4: 0, value5: 32 }, { value1: 0, value2: 9, value3: 12, value4: 0, value5: 311 }][ { value1: 1, value2: 34, value3: 13, value4: 0.5, value5: 32 }, { value1: 1, value2: 9, value3: 13, value4: 0.5, value5: 311 }][ { value1: 4, value2: 34, value3: 14, value4: 1, value5: 32 }, { value1: 4, value2: 9, value3: 14, value4: 1, value5: 311 }][ { value1: 9, value2: 34, value3: 15, value4: 1.5, value5: 32 }, { value1: 9, value2: 9, value3: 15, value4: 1.5, value5: 311 }][ { value1: 16, value2: 34, value3: 16, value4: 2, value5: 32 }, { value1: 16, value2: 9, value3: 16, value4: 2, value5: 311 }]當我控制臺.log(arr2)在for循環中時,我得到了幾乎我想要的東西,想要的結果,但不是在單個數組中。 [ { value1: 0, value2: 34, value3: 12, value4: 0, value5: 32 }, { value1: 0, value2: 9, value3: 12, value4: 0, value5: 311 }][ { value1: 1, value2: 34, value3: 13, value4: 0.5, value5: 32 }, { value1: 1, value2: 9, value3: 13, value4: 0.5, value5: 311 }][ { value1: 4, value2: 34, value3: 14, value4: 1, value5: 32 }, { value1: 4, value2: 9, value3: 14, value4: 1, value5: 311 }][ { value1: 9, value2: 34, value3: 15, value4: 1.5, value5: 32 }, { value1: 9, value2: 9, value3: 15, value4: 1.5, value5: 311 }][ { value1: 16, value2: 34, value3: 16, value4: 2, value5: 32 }, { value1: 16, value2: 9, value3: 16, value4: 2, value5: 311 }]
如何在不合并對象屬性的情況下推送對象數組以創建新數組?
倚天杖
2022-09-23 16:57:02