我創建了一個名為“alphabet”的常量，并將其分配給包含字母表前 5 個字母的數組。然后，我想要一個函數，該函數將向數組中的每個字符添加一個數字，以枚舉它們。但是，我不希望修改原始“字母表”數組中的值，因此我在枚舉函數中創建了一個“temp”變量，并且只對其進行了更改。但是，我對“temp”所做的任何更改都擴展到“字母表”。我不明白為什么，我想阻止這種情況發生。const alphabet = ["a", "b", "c", "d", "e"];function alphaPosition(seq) {  //'temp' gets 'seq' to avoid making changes directly on the provided argument.  let temp = seq;  //adds indexes to each element in the 'temp' array:  for (let i = 1; i <= temp.length; i++) {    temp[i - 1] = temp[i - 1] + i;  }  return temp;}console.log(  "Step 1. 'alphabet' array before running the 'alphaPosition' function:");console.log(alphabet);console.log(  "Step 2. This is the final value of 'temp' in 'alphaPosition' after running the function. An index has been added to every element in the array, as expected:");console.log(alphaPosition(alphabet));console.log(  "Step 3. Here's the 'alphabet' array after running 'alphaPosition'. Indexes have also been added to every element, despite not modifying the function argument directly:");console.log(alphabet);輸出：/*-> Step 1. 'alphabet' array before running the 'alphaPosition' function:-> ["a", "b", "c", "d", "e"]-> Step 2. This is the final value of 'temp' in 'alphaPosition' after running the function. An index has been added to every element in the array, as expected:-> ["a1", "b2", "c3", "d4", "e5"]-> Step 3. Here's the 'alphabet' array after running 'alphaPosition'. Indexes have also been added to every element, despite not modifying the function argument directly:-> ["a1", "b2", "c3", "d4", "e5"]*/為什么對“臨時”的更改會傳播為“字母表”？我希望，既然我把“字母表”定義為一個常量，那么甚至不應該修改它。此外，我從不在函數中對其進行更改。我只用它來定義“溫度”。有沒有辦法防止這些傳播的發生？為什么使用中間變量來避免對原始數字進行更改，而不是數組？如果對此有任何幫助或澄清，我將不勝感激。我已經將我的代碼添加到這個CodePen中，以防你想調整它或嘗試更多。提前感謝您的任何幫助。