我嘗試使用西比插值.interp2d，但我有一個問題。這是我的代碼：import scipy.interpolate as itpimport numpy as npimport matplotlib.pyplot as pltz_srtrm = 100 * np.random.rand(4,4)x_srtrm = np.arange(0,4)y_srtrm = np.arange(0,4)I = itp.interp2d(x_srtrm,y_srtrm,z_srtrm,kind='cubic') xi = np.linspace(0,4,100) yi = np.linspace(0,4,100) Z = I(xi,yi) zx = np.arange(0,100)zy = np.arange(0,100)I_inv = itp.interp2d(zx,zy,Z,kind='cubic') xj = np.linspace(0,100,4) yj = np.linspace(0,100,4) z = I_inv(xj,yj)fig = plt.figure()ax1 = fig.add_subplot(1,3,1)ax1.imshow(z_srtrm)ax2 = fig.add_subplot(1,3,2)ax2.imshow(Z)ax3 = fig.add_subplot(1,3,3)ax3.imshow(z)plt.show()通常，z_srtm應等于 z，但事實并非如此。你能解釋一下為什么嗎？提前感謝您。