我正在獲取 json 中的數組"sub": { "insert_id": [ 161, 162, 163, 164 ], "venue_id": [ "21", "3", "5", "6" ] }像這樣，我現在把它放到php變量中，我想要$allidinsert_id :[161,162,163,164] and venue_id :[21,3,5,6]
3 回答
倚天杖
TA貢獻1828條經驗 獲得超3個贊
您需要先使用，然后才能以所需的任何方式使用數據json_decode
示例（注意：不是最干凈的做事方式）：
/* Decode JSON */
$data = '{"sub":{"insert_id":[161,162,163,164],"venue_id":["21","3","5","6"]}}';
$subData = json_decode($data,true);
/* Just Loop Through Values */
foreach ($subData['sub']['insert_id'] as $sub){
echo ("<li>$sub</li>");
}
/* Create New Json */
$insertIdJson = json_encode($subData['sub']['insert_id']);
$venueIdJson = json_encode($subData['sub']['venue_id']);
echo ("Insert IDs: $insertIdJson </br>");
echo ("Venue IDs :$venueIdJson </br>");
/* Create Array Of insert_id */
$insertIdArray = json_decode(json_encode($subData['sub']['insert_id']),true);
$venueIdArray = json_decode(json_encode($subData['sub']['venue_id']),true);
var_dump($insertIdArray);
echo("</br>");
var_dump($venueIdArray);
梵蒂岡之花
TA貢獻1900條經驗 獲得超5個贊
讓我們考慮$json結果變量中的 json 響應
$json_result = "sub": {
"insert_id": [
161,
162,
163,
164
],
"venue_id": [
"21",
"3",
"5",
"6"
]
}
$result = json_decode($json_result, true);
$insert_id = $result["sub"]["insert_id"];
$venue_id = $result["sub"]["venue_id"];
echo "insert_id";
print_r($insert_id);
echo "venue_id";
print_r($venue_id);
交互式愛情
TA貢獻1712條經驗 獲得超3個贊
you can use this.
$jsonData = '{"sub":{"insert_id":[161,162,163,164],"venue_id":["21","3","5","6"]}}';
$json_result = json_decode($jsonData,true);
$insertId = $json_result["sub"]["insert_id"];
$venueId = $json_result["sub"]["venue_id"];
echo "<pre>";
print_r($insertId);
echo "<br>";
print_r($venueId);
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