我必須創建一個方法，該方法將從數組中刪除特定值，并創建一個沒有該特定值的新數組。例如，如果我的數組是 （0，2，3，5，3），而我想刪除 3，則新數組應該是 （0，2，5）。由于某種原因，它僅適用于前兩位數字。import java.util.Scanner;public class removeDemo { public static void main(String[] args) { // TODO Auto-generated method stub //array of numbers int array[] = new int[] {0,1,2,3,4,5}; //invokes method and prints result //System.out.println(remove(3,array)); remove(3,array); } //method remove that removes selected number from array public static int[] remove(int v, int[] in) { //count variable counts how many non-target numbers int count = 0; //for loop that checks if value at certain index is not equal to "v", the target number for removal for(int k = 0; k < in.length; k++) { //checks if certain number at certain index of array is not equal to v, or in this case, 3 if(in[k] != v) { //counter count++; } } //new array that will stores values except "v" int copy[] = new int[count]; //prints the length System.out.println("array length: " + copy.length); //for loop that checks if number not 3 for(int a = 1; a < in.length;) { // sets number at certain index of main array into new array if(in[a] != 3){ copy[a] = in[a]; a++; System.out.println(copy[0]); System.out.println(copy[1]); System.out.println(copy[2]); System.out.println(copy[3]); } else if(in[a] == 3) { copy[a] = in[a+1]; } } //returns new array return copy;}}如前所述，我需要新數組來排除要刪除的目標編號。
3 回答
慕萊塢森
TA貢獻1810條經驗 獲得超4個贊
您可以使用如下所示的一些代碼獲得相同的結果：
// Add to params all inputs to remove from array
List<Integer> params = new ArrayList<>();
// Use Integer class instead of int datatype
Integer array[] = new Integer[] {0,1,2,3,4,3};
// Convert array to List class
List<Integer> list = new ArrayList<>(Arrays.asList(array));
// Remove all matches
list.removeAll(params);
慕絲7291255
TA貢獻1859條經驗 獲得超6個贊
您需要兩個索引變量來進行復制：一個貫穿輸入數組（如原始代碼中所示），另一個跟蹤您在輸出數組中的位置（new 變量）。它們不能相互計算（它們在開始時是相同的，但可以明顯小于最后）abba
int b = 0;
for(int a = 0; a < in.length; a++) {
if(in[a] != v) {
copy[b] = in[a];
b++;
}
}
湖上湖
TA貢獻2003條經驗 獲得超2個贊
使用Java8及其流功能，您可以執行如下操作：
public static void main(String[] args) {
int[] array = {3236,47,34,34,73,46,3,64,473,4,4,346,4,63,644,4,6,4};
int[] newArray = removeAllOccurencesOf(array, 4);
System.out.println(Arrays.toString(newArray));
}
public static int[] removeAllOccurencesOf(int[] array, int numberToRemove)
{
//stream integers from array, filter the ones that correspond to number to remove, get what's left to new array
int[] newArray = IntStream.of(array).filter(i->i!=numberToRemove).toArray();
return newArray;
}
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