所以問題是下一個：我有POJO，比如：@Data@Accessors(chain = true)@JsonInclude(Include.NON_NULL)public class TestPOJO { private Long id; private String name; private JsonNode jsonNode;我也有json喜歡{ "id":1 "name": "foo" "jsonNode":null}當我嘗試反序列化最后一個ObjectMapper objectMapper = new ObjectMapper();TestPOJO testPojo = objectMapper.readValue(<json String>, TestPOJO.class);我在字段所在的位置獲取對象，但我需要在如何修復它？testPojojsonNodeNullNodetestPojo == null
1 回答
慕森卡
TA貢獻1806條經驗 獲得超8個贊
添加一個擴展的類，如果為 null，則返回 null：JsonDeserializer<JsonNode>parser.getText()
import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.databind.DeserializationContext;
import com.fasterxml.jackson.databind.JsonDeserializer;
import com.fasterxml.jackson.databind.JsonNode;
import java.io.IOException;
public class JsonNodeDeserializer extends JsonDeserializer<JsonNode> {
@Override
public JsonNode deserialize(JsonParser parser, DeserializationContext context)
throws IOException {
String value = parser.getText();
if(value == null) {
return null;
}
return (JsonNode) context.findRootValueDeserializer(context.constructType(JsonNode.class)).deserialize(parser, context);
}
}
然后對屬性進行注釋，以告訴 Jackson 使用您的自定義反序列化程序：jsonNode@JsonDeserialize(using = JsonNodeDeserializer.class)
@Data
@Accessors(chain = true)
@JsonInclude(Include.NON_NULL)
public class TestPOJO {
private Long id;
private String name;
@JsonDeserialize(using = JsonNodeDeserializer.class)
private JsonNode jsonNode;
// getters and setters
}
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