以下是我的JSON：{ "time":{ "date":{ "year":2017, "month":3, "day":12 }, "time":{ "hour":10, "minute":42, "second":42, "nano":810000000 } },"name":"Jon","message":{"product":"orange""price":2000}}“時間”字段有一個嵌套的“時間”字段。我如何使用杰克遜解析它到java對象。任何人都可以告訴我正確的方法嗎？
3 回答
jeck貓
TA貢獻1909條經驗 獲得超7個贊
您可以創建如下類：
class JavaObject {
private TimeObject time;
private String name;
//other fields
//getters and setters
}
class TimeObject {
private Date date;
private Time time;
//getters and setters
}
class Date {
private int year;
private int month;
private int day;
//getters and setters
}
class Time {
private int hour;
private int minute;
private int second;
private long nano;
//getters and setters
}
完成后，您可以使用 將 String 反序列化為對象，例如：JacksonjsonJavaObject
ObjectMapper objectMapper = new ObjectMapper();
JavaObject javaObject = objectMapper.readValue("{\n" +
" \"time\":{\n" +
" \"date\":{\n" +
" \"year\":2017,\n" +
" \"month\":3,\n" +
" \"day\":12\n" +
" },\n" +
" \"time\":{\n" +
" \"hour\":10,\n" +
" \"minute\":42,\n" +
" \"second\":42,\n" +
" \"nano\":810000000\n" +
" }\n" +
" },\n" +
"\"name\":\"Jon\"}", JavaObject.class);
System.out.println(javaObject);
DIEA
TA貢獻1820條經驗 獲得超2個贊
如果你只需要內部對象，你可以用一種快速的方式做到這一點：time
// your POJO class
// (public fields sould be private with getter & setter, of course)
public class Pojo {
public int hour;
public int minute;
public int second;
public long nano;
@Override
public String toString() {
return hour + ":" + minute + ":" + second + ":" + nano;
}
}
然后：
//your json string
String jsonString = "{\"time\":{\"date\":{\"year\":2017,\"month\":3,\"day\":12},"
+ "\"time\":{\"hour\":10,\"minute\":42,\"second\":42,\"nano\":810000000}},"
+ "\"name\":\"Jon\",\"message\":{\"product\":\"orange\",\"price\":2000}}";
ObjectMapper mapper = new ObjectMapper();
JsonNode jsonRoot = mapper.readTree(jsonString); //parse string to JsonNode
Pojo pojo = mapper.treeToValue(jsonRoot.at("/time/time"), Pojo.class); //create Pojo instance from inner time object
System.out.println(pojo); //see if it worked
這打?。?/p>
10:42:42:810000000
明月笑刀無情
TA貢獻1828條經驗 獲得超4個贊
使用杰克遜庫
ObjectMapper jsonMapper= new ObjectMapper();
YourCorrespondingObject object = jsonMapper.readValue("your json as string...", YourCorrespondingObject.class);
首先構建對象，填充它并轉換為字符串更容易，以確保它等于現有字符串，例如：
String jsonInString = mapper.writeValueAsString(object);
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