我有一個python中的元組列表。list = [(1,2), (1,3), (1,4), (2,3), (2, 4), (3,4)]如何打印所有可能的元組對？我想避免重復。例如 ，（1，2）、（2，3） 和 （2，3）、（1，2） 是重復的。預期結果是：(1,2), (1,3)(1,2), (1,4)(1,2), (2,3)(1,2), (2,4)(1,2), (3,4)(1,3), (1,4)(1,3), (2,3)(1,3), (2,4)(1,3), (3,4)(1,4), (2,3)(1,4), (2,4)(1,4), (3,4)(2,3), (2,4)(2,3), (3,4)(2,4), (3,4)
2 回答
牧羊人nacy
TA貢獻1862條經驗 獲得超7個贊
看看迭代工具中的組合。
>>> l = [(1,2), (1,3), (1,4), (2,3), (2, 4), (3,4)]
>>> import itertools
>>> combinations = itertools.combinations(l, 2)
>>> for combination in combinations:
... print(combination)
...
((1, 2), (1, 3))
((1, 2), (1, 4))
((1, 2), (2, 3))
((1, 2), (2, 4))
((1, 2), (3, 4))
((1, 3), (1, 4))
((1, 3), (2, 3))
((1, 3), (2, 4))
((1, 3), (3, 4))
((1, 4), (2, 3))
((1, 4), (2, 4))
((1, 4), (3, 4))
((2, 3), (2, 4))
((2, 3), (3, 4))
((2, 4), (3, 4))
紅顏莎娜
TA貢獻1842條經驗 獲得超13個贊
試試這個代碼：
from itertools import combinations
# Get all combinations and length 2
comb = combinations([(1,2), (1,3), (1,4), (2,3), (2, 4), (3,4)], 2)
# Print the obtained combinations
for i in list(comb):
print(i[0],",", i[1])
輸出：
(1, 2) , (1, 3)
(1, 2) , (1, 4)
(1, 2) , (2, 3)
(1, 2) , (2, 4)
(1, 2) , (3, 4)
(1, 3) , (1, 4)
(1, 3) , (2, 3)
(1, 3) , (2, 4)
(1, 3) , (3, 4)
(1, 4) , (2, 3)
(1, 4) , (2, 4)
(1, 4) , (3, 4)
(2, 3) , (2, 4)
(2, 3) , (3, 4)
(2, 4) , (3, 4)
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