我正在努力實現以下目標：我有一個電子郵件對象（eml），它可以包含多個附件，如zip /images/ txt等。我只想下載一個特定的附件，而不是從這個對象下載所有附件。我嘗試了以下代碼：import emailimport mimetypesimport uuidimport osm = email.message_from_file(open('hello.eml'))for part in m.walk():filename = part.get_filename()print('fileName: ', filename)if part.get_content_type() == 'multipart/mixed' and not filename: number_of_attachments = (len(part.get_payload()) - 1) print('number_of_attachments: ', number_of_attachments) for attachment in range(number_of_attachments): tmp_name = str(uuid.uuid4()) fp = open('.' + tmp_name, 'wb') attachment += 1 fp.write(part.get_payload()[attachment].get_payload(decode=True)) fp.close()這將提取所有附件。有沒有辦法只過濾特定的附件并處理它。任何幫助都非常感謝！
1 回答
慕尼黑8549860
TA貢獻1818條經驗 獲得超11個贊
所以，我找到了以下方法。
import email
import mimetypes
import uuid
import os
m = email.message_from_file(open('hello.eml'))
for part in m.walk():
filename = part.get_filename()
print('fileName: ', filename)
if part.get_content_type() == 'multipart/mixed' and not filename:
number_of_attachments = (len(part.get_payload()) - 1)
print('number_of_attachments: ', number_of_attachments)
for attachment in range(number_of_attachments):
filteredFile = m.get_payload()[attachment]
if filteredFile.get_content_type() == 'text/html':
print("Search successful.")
else:
print("Search unsuccessful.")
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