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簡化嵌套對象并查找特定屬性的總和

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簡化嵌套對象并查找特定屬性的總和

JavaScript

慕容森 2022-09-02 10:25:40

我有一個嵌套的對象，如下所示。我想將嵌套對象簡化為一個對象，并查找特定父對象的所有子級的特定屬性的總和。當前對象let obj = {Myanmar: [ { trk1: { mou: 0.0, ca: 1.0, ccs: 0.0, ccc: 0.0, }, }],Gibraltar: [ { trk1: { mou: 12.850000381469727, ca: 1.0, ccs: 1.0, ccc: 3.0, }, }],Cyprus: [ { trk1: { mou: 36.25, ca: 3.0, ccs: 2.0, ccc: 7.0, }, trk2: { mou: 27.299999237060547, ca: 1.0, ccs: 1.0, ccc: 6.0, }, trk3: { mou: 80.59999752044678, ca: 4.0, ccs: 4.0, ccc: 14.0, }, trk4: { mou: 26.716670513153076, ca: 4.0, ccs: 4.0, ccc: 6.0, } }]};預期對象{Myanmar: { mou: "(trk1-mou+trk2-mou+trk3-mou)", ca: "(trk1-ca+trk2-ca+trk3-ca)"}};我想對嵌套對象執行屬性的總和。我無法繼續后得到對象.鍵請幫助.

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2 回答

白豬掌柜的

TA貢獻1893條經驗獲得超10個贊

我不確定這是否是你想要的：

var obj={"Myanmar": [{ "trk1": { "mou": 0.0, "ca": 1.0, "ccs": 0.0, "ccc": 0.0 }}],"Gibraltar": [{ "trk1": { "mou": 12.850000381469727, "ca": 1.0, "ccs": 1.0, "ccc": 3.0 }}],"Cyprus": [{ "trk1": { "mou": 36.25, "ca": 3.0, "ccs": 2.0, "ccc": 7.0 }, "trk2": { "mou": 27.299999237060547, "ca": 1.0, "ccs": 1.0, "ccc": 6.0 }, "trk3": { "mou": 80.59999752044678, "ca": 4.0, "ccs": 4.0, "ccc": 14.0 }, "trk4": { "mou": 26.716670513153076, "ca": 4.0, "ccs": 4.0, "ccc": 6.0 }}]}

result = Object.entries(obj).reduce((acc, [k,v])=>{

acc[k] = acc[k] || {};

Object.entries(v[0]).forEach(([_, country])=>{

for(let [key, value] of Object.entries(country)){

acc[k][key] = acc[k][key] || 0;

acc[k][key] += value;

}

})

return acc;

},{});

console.log(result);

反對回復 2022-09-02

長風秋雁

TA貢獻1757條經驗獲得超7個贊

let reqObj={};

let arr = Object.keys(obj);

for(var i=0;i<=arr.length-1;i++){

let inObj = obj[arr[i]][0];

reqObj[arr[i]] = Object.keys(inObj).reduce((acc,ele,index)=>{

let keyArr = Object.keys(inObj[ele]);

for(var j=0;j<=keyArr.length-1;j++){

acc = {...acc,...{[keyArr[j]] : (keyArr[j] in acc) ? acc[keyArr[j]] + inObj[ele][keyArr[j]] : inObj[ele][keyArr[j]]}}

}

return acc;

},{})

}

console.log(reqObj)

反對回復 2022-09-02

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簡化嵌套對象并查找特定屬性的總和

簡化嵌套對象并查找特定屬性的總和

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