任務： You are making a robot that can speak numbers. Your robot should take 3 numbers in the range of 0-10 as input and output the corresponding texts in English.預解決方案：演示func main() {num := 0var input intfor i := 0; i < 10; i++ { num += 1 switch num { case 1: fmt.Println("One") case 2: fmt.Println("Two") case 3: fmt.Println("Three") case 4: fmt.Println("Four") case 5: fmt.Println("Five") case 6: fmt.Println("Six") case 7: fmt.Println("Seven") case 8: fmt.Println("Eight") case 9: fmt.Println("Nine") case 10: fmt.Println("Ten") }}}問題：如何運行循環 3 次？更多詳情： https://www.sololearn.com/learning/eom-project/1164/1188
2 回答
翻閱古今
TA貢獻1780條經驗 獲得超5個贊
這似乎做到了：
package main
import "fmt"
func robot(d, e, f int) (string, string, string) {
m := map[int]string{
0: "zero", 1: "one", 2: "two", 3: "three", 4: "four",
5: "five", 6: "six", 7: "seven", 8: "eight", 9: "nine", 10: "ten",
}
return m[d], m[e], m[f]
}
func main() {
s, t, u := robot(1, 2, 3)
fmt.Printf("%q %q %q\n", s, t, u)
}
largeQ
TA貢獻2039條經驗 獲得超8個贊
該任務指出，您需要使輸入3位數字，輸出應該有文本，我做到了并傳遞了所有
package main
import "fmt"
func main() {
var input int
var i = 1
for {
fmt.Scanln(&input)
if input >= 0 && input <= 10 {
switch input {
case 0:
fmt.Println("Zero")
case 1:
fmt.Println("One")
case 2:
fmt.Println("Two")
case 3:
fmt.Println("Three")
case 4:
fmt.Println("Four")
case 5:
fmt.Println("Five")
case 6:
fmt.Println("Six")
case 7:
fmt.Println("Seven")
case 8:
fmt.Println("Eight")
case 9:
fmt.Println("Nine")
case 10:
fmt.Println("Ten")
}
if i == 3 {
break
}
i++
}
}
}
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