首頁猿問將對象數組與公共值組合在一起，并為...

將對象數組與公共值組合在一起，并為每個對象返回一個鍵和值

JavaScript

慕森王 2022-08-27 09:21:01

[{id: 68, name: "IT"}{id: 67, name: "IT"}{id: 66, name: "Supply chain"}{id: 65, name: "Manufacturing Engineering"}{id: 64, name: "Sales & Marketing"}{id: 63, name: "Research and Development"}{id: 62, name: "Research and Development"}{id: 61, name: "Research and Development"}] 請采取任何手段來實現這一點？.我想通過它來選擇選項來獲取相應的ID和名稱[ {1: IT2: Supply Chain,3: Research and Development}]

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3 回答

汪汪一只貓

TA貢獻1898條經驗獲得超8個贊

因此，以下內容為您提供了所需的輸出，但我懷疑還有其他因素可能沒有考慮在內（例如，維護ID，排序等）。

鑒于：

const input = [

{id: 68, name: "IT"},

{id: 67, name: "IT"},

{id: 66, name: "Supply chain"},

{id: 65, name: "Manufacturing Engineering"},

{id: 64, name: "Sales & Marketing"},

{id: 63, name: "Research and Development"},

{id: 62, name: "Research and Development"},

{id: 61, name: "Research and Development"},

];

我們可以：

const output = [...new Set(

// Get a unique set of department names

input.map(i => i.name)

)].map(

// With the new set of department names

// Reconstruct the list with id values starting at 1 instead of 0

(dept, idx) => ({

id: idx + 1,

name: dept,

})

);

反對回復 2022-08-27

不負相思意

TA貢獻1777條經驗獲得超10個贊

后來，您可以利用首先過濾掉重復值，然后相應地映射它。以下是操作方法：Map

var data = [{id: 68, name: "IT"},{id: 67, name: "IT"},{id: 66, name: "Supply chain"},{id: 65, name: "Manufacturing Engineering"},{id: 64, name: "Sales & Marketing"},{id: 63, name: "Research and Development"},{id: 62, name: "Research and Development"},{id: 61, name: "Research and Development"}];

var result1 = [...new Map(data.map(val=>[val.name, val])).values()];

var result2 = [...new Map(data.map(val=>[val.name, val])).values()].map(({id, name},i)=>({id:i+1, name}));

console.log(result1)

console.log(result2);

反對回復 2022-08-27

暮色呼如

TA貢獻1853條經驗獲得超9個贊

如果您使用 rxjs，則可以使用此解決方案。

this.data = [...] // array

from(this.data)

.pipe(

distinct(data => data.name),

map(data => data.name),

toArray(),

map(names => ({...names}))

).subscribe(

console.log

);

反對回復 2022-08-27

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將對象數組與公共值組合在一起，并為每個對象返回一個鍵和值

將對象數組與公共值組合在一起，并為每個對象返回一個鍵和值

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將對象數組與公共值組合在一起，并為每個對象返回一個鍵和值

將對象數組與公共值組合在一起，并為每個對象返回一個鍵和值