在對多對多關系使用額外列時，我找不到一種干凈簡單的方法來進行分頁。我的模型看起來像這樣：我有一個用戶和一個產品模型。每個用戶可以消費n種產品。每個消耗將存儲在一個額外的表中，因為我想存儲額外的信息，如日期等。我已經實現了如下模型并且它的工作原理，但我想將用戶的消費作為可尋呼的，而不是檢索整個集合。實現它的最佳方法是什么？@Entitypublic class User { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @OneToMany( mappedBy = "user", cascade = CascadeType.ALL, orphanRemoval = true ) private List<Consumption> consumptionList = new ArrayList<>(); // never set this attribute public List<Consumption> getConsumptionList() { return consumptionList; } public void addConsumption(Product product) { Consumption consumption = new Consumption(this, product); consumptionList.add(consumption); product.getConsumptionList().add(consumption); } public void removeConsumption(Consumption consumption) { consumption.getProduct().getConsumptionList().remove(consumption); consumptionList.remove(consumption); consumption.setUser(null); consumption.setProduct(null); }}--@Entity@[email protected](usage = CacheConcurrencyStrategy.READ_WRITE)public class Product { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @OneToMany( mappedBy = "product", cascade = CascadeType.ALL, orphanRemoval = true ) private List<Consumption> consumptionList = new ArrayList<>(); public List<Consumption> getConsumptionList() { return consumptionList; }}這是我存儲消耗的類。@Entitypublic class Consumption { @EmbeddedId private UserProductId id; @ManyToOne(fetch = FetchType.LAZY) @MapsId("userId") private User user;}我希望能夠調用一個方法，例如“getConsumptionList（Page page）”，然后返回一個Pageable。我希望你能幫助我！
2 回答
ibeautiful
TA貢獻1993條經驗 獲得超6個贊
好吧，如果使用Spring Boot，你可以使用存儲庫：
@Repository
public interface ConsumptionRepo extends JpaRepository<Consumption, Long>{
List<Consumption> findByUser(User user, Pageable pageable);
}
然后你可以簡單地調用它
ConsumptionRepo.findByUser(user, PageRequest.of(page, size);
MMTTMM
TA貢獻1869條經驗 獲得超4個贊
由于@mtshaikh想法，我終于為我的問題找到了解決方案：
只需實現一個分頁服務：
public Page<Consumption> getConsumptionListPaginated(Pageable pageable) {
int pageSize = pageable.getPageSize();
int currentPage = pageable.getPageNumber();
int startItem = currentPage * pageSize;
List<Consumption> list;
if (consumptionList.size() < startItem) {
list = Collections.emptyList();
} else {
int toIndex = Math.min(startItem + pageSize, consumptionList.size());
list = consumptionList.subList(startItem, toIndex);
}
return new PageImpl<>(list, PageRequest.of(currentPage, pageSize), consumptionList.size());
}
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