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在執行正確的代碼后,如何阻止我的代碼執行每個 println?

在執行正確的代碼后,如何阻止我的代碼執行每個 println?

慕婉清6462132 2022-08-17 10:22:50
 Scanner scan = new Scanner(System.in);    System.out.print("Enter 2 numbers: ");    int num1 = scan.nextInt();    int num2 = scan.nextInt();    System.out.println("Numbers Saved! Choose your operator + - * / ");    String operator = scan.next();    int result;    result = (operator.equals("+")) ? (num1 + num2) : (num1);    System.out.println("The addition result is " +result);    result = (operator.equals("-")) ? (num1 - num2) : (num1);    System.out.println("The subtraction result is " +result);    result = (operator.equals("*")) ? (num1 * num2) : (num1);    System.out.println("The multiplication result is " +result);    result = (operator.equals("/")) ? (num1 / num2) : (num1);    System.out.println("The division result is " +result);}}這是我的簡單計算器代碼,例如,當我選擇+選項時,它會運行所有System.out.println行,我如何防止它這樣做并且只執行與運算符匹配的println?
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2 回答

?
喵喵時光機

TA貢獻1846條經驗 獲得超7個贊

嘗試切換:


switch (operator) {

    case "+":

        result = num1 + num2;

        System.out.println("The addition result is " + result);

        break;

    case "-":

        result = num1 - num2;

        System.out.println("The subtraction result is " + result);

        break;

    case "-":

        result = num1 * num2;

        System.out.println("The multiplication result is " + result);

        break;

    case "/":

        result = num1 / num2;

        System.out.println("The integer division result is " + result);

        break;

    default:

        throw IllegalArgumentException("Unsupported operator: " + operator);

}


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?
DIEA

TA貢獻1820條經驗 獲得超2個贊

我將運算符邏輯(分辨率和評估)封裝到 .喜歡enum


enum Oper {

    ADDITION("+"), SUBTRACTION("-"), MULTIPLICATION("*"), DIVISION("/");

    Oper(String symbol) {

        this.symbol = symbol;

    }


    public int eval(int a, int b) {

        switch (this) {

        case ADDITION: return a + b;

        case SUBTRACTION: return a - b;

        case MULTIPLICATION: return a * b;

        case DIVISION: return a / b;

        }

        return -1;

    }


    private String symbol;


    public static Oper from(String operator) {

        for (Oper o : values()) {

            if (o.symbol.equals(operator)) {

                return o;

            }

        }

        return null;

    }

}

這簡化了 中的邏輯,只需解析運算符并對其進行求值即可。喜歡main


Oper o = Oper.from(operator);

System.out.printf("The %s result is %d%n", o.name().toLowerCase(), o.eval(num1, num2));



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