我試圖寫一個石頭剪刀槍程序，其中選擇是1，2和3。我想驗證輸入，以便除這三個選項之外的任何輸入都將打印一條消息，指出輸入有效，并要求用戶重新輸入數據。我有一些工作，但是，即使我輸入1 2或3，它仍然會打印消息并要求更多輸入。print("This program simulates a 'rock paper scissor' game.")print("The rules are as follows: rock beats scissor, paper beats rock, and scissor beats paper. \n")print("This program simulates a 'rock paper scissor' game.")print("The rules are as follows: rock beats scissor, paper beats rock, and scissor beats paper. \n")#get user inputuser_choice = input("Please choose from the following: \n" " 1 for scissor \n" " 2 for rock \n" " 3 for paper. \n")#validate input so user only enters 1, 2, or 3while user_choice != 1 or user_choice != 2 or user_choice != 3: user_choice = input("Please enter only '1' for scissor, '2' for rock, or '3' for paper: ")#convert input to int int_user_choice = int(user_choice)
4 回答
陪伴而非守候
TA貢獻1757條經驗 獲得超8個贊
如果要稍后將輸入與整數進行比較，則需要將輸入從字符串轉換為整數。如果你想避免一遍又一遍地重復邏輯，你可以使用列表。
user_choice = int(input("Please choose from the following: \n"
" 1 for scissor \n"
" 2 for rock \n"
" 3 for paper. \n"))和
while user_choice not in [1,2,3]
手掌心
TA貢獻1942條經驗 獲得超3個贊
在單個循環中執行整個提示/驗證。在滿足條件之前，用戶無法繼續
print("This program simulates a 'rock paper scissor' game.")
print("The rules are as follows: rock beats scissor, paper beats rock, and scissor beats paper. \n")
print("This program simulates a 'rock paper scissor' game.")
print("The rules are as follows: rock beats scissor, paper beats rock, and scissor beats paper. \n")
#get user input
while True:
user_choice = input("Please choose from the following: \n"
" 1 for scissor \n"
" 2 for rock \n"
" 3 for paper. \n")
#validate input so user only enters 1, 2, or 3
if user_choice in ["1", "2", "3"]:
int_user_choice = int(user_choice)
break
江戶川亂折騰
TA貢獻1851條經驗 獲得超5個贊
您的不正確，因為輸入返回字符串類型，并且您正在使用類型int進行檢查，因此請在循環中更改類型。此外，如果希望它在其中一種情況下終止，則不能使用，在這種情況下，您必須使用 。orand
print("This program simulates a 'rock paper scissor' game.")
print("The rules are as follows: rock beats scissor, paper beats rock, and scissor beats paper. \n")
print("This program simulates a 'rock paper scissor' game.")
print("The rules are as follows: rock beats scissor, paper beats rock, and scissor beats paper. \n")
#get user input
user_choice = input("Please choose from the following: \n"
" 1 for scissor \n"
" 2 for rock \n"
" 3 for paper. \n")
#validate input so user only enters 1, 2, or 3
while user_choice != '1' and user_choice != '2' and user_choice != '3':
user_choice = input("Please enter only '1' for scissor, '2' for rock, or '3' for paper: ")
#convert input to int
int_user_choice = int(user_choice)
收到一只叮咚
TA貢獻1821條經驗 獲得超5個贊
獲得輸入后，您可以檢查兩個輸入是否都是有效數字并且它是否在有效范圍內，如果兩個條件之一不成立，請再次請求輸入。
valid_choices = {1,2,3}
while not user_choice.isdigit() and not int(user_choice) in valid_choices:
user_choice = input("Please enter only '1' for scissor, '2' for rock, or '3' for paper: ")
或更簡單地說
valid_choices = {'1','2','3'}
while not user_choice in valid_choices:
user_choice = input("Please enter only '1' for scissor, '2' for rock, or '3' for paper: ")
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