我的代碼是:$result = 20201601; //fetched from a source as string//Convert string to date format 'Y/m/d'$date1 = substr($result, 0, 4) . '/' . substr($result, 4, 2) . '/' . substr($result, 6, 2); echo $date1 . "<br>";//Add 30 days to it$date2 = date('Y/m/d', strtotime('+30 days', strtotime($date1)));echo $date2;if ($date2 < date('Y/m/d', strtotime('now'))){ //If date fetched ($result) is older than 30 days from today's date, then fetch new date from source}代碼無法在以下位置添加 30 天:,它給出:date('Y/m/d', strtotime('+30 days', strtotime($date1)))1970/01/30
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一只萌萌小番薯
TA貢獻1795條經驗 獲得超7個贊
改變
$date1 = substr($result, 0, 4) . '/' . substr($result, 4, 2) . '/' . substr($result, 6, 2);
自
$date1 = substr($result, 0, 4) . '/' . substr($result, 6, 2) . '/' . substr($result, 4, 2);
這是必需的,因為您當前的數據的格式為 。一個月不能有值。20201601
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