我有這個代碼來創建RSA 4096公鑰和私鑰來加密和解密字符串。法典：<?php$config = array( "config" => "C:/xampp/php/extras/openssl/openssl.cnf", "private_key_bits" => 4096, "private_key_type" => OPENSSL_KEYTYPE_RSA);// Create the private and public key$res = openssl_pkey_new($config);// Extract the private key from $res to $privKeyopenssl_pkey_export($res, $privKey);// Extract the public key from $res to $pubKey$pubKey = openssl_pkey_get_details($res);$pubKey = $pubKey["key"];$data = 'Hello, World!';// Encrypt the data to $encrypted using the public keyopenssl_public_encrypt($data, $encrypted, $pubKey);echo $encrypted;// Decrypt the data using the private key and store the results in $decryptedopenssl_private_decrypt($encrypted, $decrypted, $privKey);echo $decrypted;?>它創建密鑰，加密字符串 （），但當嘗試解密字符串時，會發生錯誤：dataHello, World!encrypted警告：openssl_private_decrypt（）： 在第 26 行的 C：\xampp\htdocs\rsa\index.php 密鑰參數不是有效的私鑰
2 回答
慕萊塢森
TA貢獻1810條經驗 獲得超4個贊
好吧，這對我有用：
更改為 。openssl_pkey_export($res, $privKey);openssl_pkey_export($res, $privKey, NULL, $config);
RISEBY
TA貢獻1856條經驗 獲得超5個贊
您不需要像這樣導出密鑰私有，至少在將其保存在安全的地方之前是這樣：
$config = array(
"private_key_bits" => 4096,
"private_key_type" => OPENSSL_KEYTYPE_RSA
);
$pki = openssl_pkey_new($config);
$public = openssl_pkey_get_public(
openssl_pkey_get_details($pki)['key']
); // why on earth did they implement it like this? so clunky.
$private = openssl_pkey_get_private($pki);
$data = 'Hello, World!';
openssl_public_encrypt($data, $encrypted, $public);
openssl_private_decrypt($encrypted, $decrypted, $private);
var_dump(
bin2hex($encrypted),
$decrypted
);
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