我想通過使用JAXB取消編組將XML轉換為java。這是我的員工.xml。我試圖轉換，但它顯示錯誤javax.xml.bind.UnmarshalException<?xml version="1.0" encoding="UTF-8"?><deptname name="Research"> <employee> <eid>r-001</eid> <ename>Dinesh R</ename> <age>35</age> <deptcode>d1</deptcode> <deptname>Research</deptname> <salary>20000</salary></employee></deptname><deptname name="Sales"><employee> <eid>s-001</eid> <ename>Kanmani S</ename> <age>35</age> <deptcode>d2</deptcode> <deptname>Sales</deptname> <salary>30000</salary> </employee> </deptname><deptname name="Delivery"> <employee> <eid>d-001</eid> <ename>Kanchana M</ename> <age>35</age> <deptcode>d3</deptcode> <deptname>Delivery</deptname> <salary>20000</salary></employee> </deptname>
1 回答
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TA貢獻1775條經驗 獲得超8個贊
根據 XML 文檔，您只能有一個根元素，因此應將 xml 更改為：
<?xml version="1.0" encoding="UTF-8"?>
<departments>
<deptname name="Research">
<employee>
<eid>r-001</eid>
<ename>Dinesh R</ename>
<age>35</age>
<deptcode>d1</deptcode>
<deptname>Research</deptname>
<salary>20000</salary>
</employee>
</deptname>
<deptname name="Sales">
<employee>
<eid>s-001</eid>
<ename>Kanmani S</ename>
<age>35</age>
<deptcode>d2</deptcode>
<deptname>Sales</deptname>
<salary>30000</salary>
</employee>
</deptname>
<deptname name="Delivery">
<employee>
<eid>d-001</eid>
<ename>Kanchana M</ename>
<age>35</age>
<deptcode>d3</deptcode>
<deptname>Delivery</deptname>
<salary>20000</salary>
</employee>
</deptname>
</departments>
然后，您需要一個類部門來閱讀該文章：
@XmlRootElement(name="departments")
public class Departments {
List<Department> deptname;
// Getters and setters
}
測試用例是：
@Test
public void testXML() {
try {
File file = new File("./src/main/resources/employee.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(Departments.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
Departments departments = (Departments) jaxbUnmarshaller.unmarshal(file);
System.out.println(departments);
} catch (JAXBException e) {
e.printStackTrace();
}
}
其次，您沒有“研究”或“銷售”或“交付”屬性，您有一個可以采用任何字符串值的屬性“name”，因此您需要更改實現：
public class Department {
@XmlAttribute(name = "name")
private String name;
@XmlElement(name = "employee")
private List<Employee> employee = new ArrayList<>();
// Getters and setters
}
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