我在 Laravel 中定義了 3 個表,如下所示:Schema::create('locales', function (Blueprint $table) { $table->string('id', 2); $table->string('name', 5000); $table->timestamps(); $table->primary('id');});Schema::create('i18n_keys', function (Blueprint $table) { $table->string('id', 255); $table->timestamps(); $table->primary('id');});Schema::create('i18ns', function (Blueprint $table) { $table->bigIncrements('id'); $table->string('key', 255); $table->string('locale', 2); $table->string('translation', 5000)->nullable(); $table->timestamps(); $table->foreign('key')->references('id')->on('i18n_keys')->onDelete('cascade')->onUpdate('cascade'); $table->foreign('locale')->references('id')->on('locales')->onDelete('cascade')->onUpdate('cascade'); $table->unique(array('key', 'locale'));});現在的問題是如何SELECT以編程方式在 Laravel 中實現以下語句。我的意思是不直接運行 SQL 語句。SELECT `il`.`key`, `il`.`locale`, `in`.`translation` FROM (SELECT `ik`.`id` AS `key`, `lo`.`id` AS `locale` FROM `i18n_keys` as `ik` CROSS JOIN `locales` as `lo`) AS `il` left join `i18ns` as `in` ON `in`.`key` = `il`.`key` and `in`.`locale` = `il`.`locale`;目的是提取他們還沒有翻譯的鍵。但我喜歡使用查詢生成器或 eloquent 或類似的東西來執行此操作,而不是直接傳遞查詢。有什么辦法嗎?
1 回答

慕沐林林
TA貢獻2016條經驗 獲得超9個贊
你可以試試這段代碼:
use App\Models\I18nKey;
$ik = I18nKey::crossJoin('locales as lo')
->select('i18n_keys.id AS key', 'lo.id AS locale');
$res = \DB::table(\DB::raw("({$ik->toSql()}) AS il"))
->mergeBindings($ik->getQuery())
->leftjoin('i18ns as in',function($join){
$join->on('in.key', '=', 'il.key')
->whereColumn('in.locale', 'il.locale');
})->select('il.key','il.locale','in.translation')->get();
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